All categories

3 years ago

‼️‼️‼️HELP‼️‼️‼️‼️‼️

Mathematics

1 answer:

horsena [70]3 years ago

4 0

<h3>Option B: Supplementary angles; x = 62</h3>

In the diagram, we can see that the angles are linear pair, which means they are of 180°. Now,

Supplementary angles are those which form an angle of 180° where as Complementary angles are those which form an angle of 90°. Certainly, the as it is a linear pair, they both are supplementary angles.

Now, we can say that:

= x + 118 = 180 ------------ [ Supplementary angles]

= x = 180 - 118

= x = 62

That's how the option B is correct.

You might be interested in

I GIVEEE BRAINLI8LSTT C

Paul [167]

Answer:

3,-2.

Step-by-step explanation:

hope this helps. :-)

5 0

3 years ago

Read 2 more answers

HELP EASY PLS ITS TIMED

marta [7]

Answer:

its 3

Step-by-step explanation:

i hope that is right

much love

<33

8 0

3 years ago

Read 2 more answers

Using the following equation, find the center and radius: x2 −2x + y2 − 6y = 26 (5 points)

Lisa [10]

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

$x^2-2x + y^2 - 6y = 26$

Typically, the equation of a circle would be in the form $(x-h)^2+(y-k)^2=r^2$ where $(h,k)$ is the center and $r$ is the radius.

To get the given equation $x^2-2x + y^2 - 6y = 26$ into this form, we must complete the square for both x and y.

1) Complete the square for x

Let's take a look at this part of the equation:

$x^2-2x$

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

$x^2-2x+1$

Great! Now, let's add this to our original equation:

$x^2-2x+1+y^2-6y = 26$

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

$x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27$

Complete the square:

$(x-1)^2+y^2-6y = 27$

2) Complete the square for y

Let's take a look at this part of the equation $(x-1)^2+y^2-6y = 27$ :

$y^2-6y$

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

$y^2-6y+9$

Great! Now, back to our original equation:

$(x-1)^2+y^2-6y+9= 27$

Remember to add 9 on the other side as well:

$(x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36$

Complete the square:

$(x-1)^2+(y-3)^2= 36$

3) Determine the center and the radius

$(x-1)^2+(y-3)^2= 36$

$(x-h)^2+(y-k)^2=r^2$

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

3 0

3 years ago

Read 2 more answers

A new video game is on sale for $54.99. Write a function rule for how much revenue, , will the store make for selling copies of

Gekata [30.6K]

So, if each one costs $54.99

Let "X" be the number of games sold, Let R(X) be the revenue

$R(x)=54.99x$

This function is continuous

6 0

4 years ago

Richard has a rectangular plot of land that is 525 feet long and y feet wide. He decides to build a fence around the plot. If th

mart [117]

Answer:

Step-by-step explanation:

P= 2(L) + 2(w)

1504= 2(525) + 2(w)

1540= 1050 + 2(w)

1540 - 1050= 2(w)

490 = 2(w)

490/2 = w

245 = w

w is y

L is 525

5 0

3 years ago

Read 2 more answers