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slega [8]
3 years ago
8

Find any points of discontinuity for each rational function. Sketch a graph. Describe any verticals or horizontal asympyoyes and

any holes
(X^2-4)/(X+2)(X^2-49)

Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0
For
  y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
  y = (x -2)/(x^2 -49)

There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.

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3 years ago
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What is the equation of the line ?
Ronch [10]

Look at the picture.

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-3, -3) and (2, 0). Substitute:

m=\dfrac{0-(-3)}{2-(-3)}=\dfrac{3}{5}\\\\y-0=\dfrac{3}{5}(x-2)\qquad|\text{use distributive property}\\\\y=\dfrac{3}{5}x-\dfrac{6}{5}\qquad|\cdot5\\\\5y=3x-6\qquad|-5y\\\\0=3x-5y-6\qquad|+6\\\\3x-5y=6

Answer:

point-slope form: y=\dfrac{3}{5}(x-2)

slope-intercept form: y=\dfrac{3}{5}x-\dfrac{6}{5}

standard form: 3x-5y=6

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3 years ago
(2-5i)(4+7i)? How do u do this? HELPPPPPPPP
krek1111 [17]
The "I"'s r variables, now u do 2-5 which sequels -2. now u do 4+7 and that ='s 11. now I think u take 11 and -2 and u subtract 11-(-2). or it could be change the negative into a positive and add them together.
3 0
3 years ago
Simplify the expression
GREYUIT [131]
√12
= √4 * <span>√3
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------------------</span>
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Please help urgently ​
jenyasd209 [6]

Answer: no real solution

Thus, the function has no x- intercept

Step-by-step explanation:

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