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3 years ago

Can someone help me find the x

Mathematics

2 answers:

marta [7]3 years ago

8 0

can you tell me what your doing here and might help.

11Alexandr11 [23.1K]3 years ago

3 0

Answer:

Step-by-step explanation:

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Write a positive or negative integer that represents the situation. You lose 38 coins in a video game.

ikadub [295]

What are we supposed to do about you losing coins? could you show an image.

5 0

2 years ago

HELP DUE IN 15 MINS!

Stells [14]

Answer:

n = 18

Step-by-step explanation:

<u>Sum of interior angles of a polygon:</u>

(n - 2)180 = 160n
180n - 360 = 160n
20n = 360
n = 18

8 0

3 years ago

Can a triangle be formed with the sides lengths of 8 cm, 5 cm and 13 cm?

Anni [7]

The rule says that the sum of any two sides has to be smaller than the third side so, no it can't

4 0

3 years ago

Steve uses ⅜ gallon of paint to paint 4 identical birdhouses. How many gallons of paint does he use for each birdhouse? Plz hurr

Lelu [443]

Answer:

But of coarse, we need to set one up. 8/9 gallons of paint for 4 birdhouses. Divide 4 by both sides. Our answer is that for each birdhouse, he use about 0.22 gallons of paint. thank me later

3 0

3 years ago

If a computer network has 60 switching nodes, in how many ways can 2 or 3 nodes fail?___________

notka56 [123]

Answer:

There are 35990 ways in which 2 or 3 nodes fail

Step-by-step explanation:

Given : A computer network has 60 switching nodes.

To Find : In how many ways can 2 or 3 nodes fail?

Solution:

We are supposed to find no. of ways can 2 or 3 nodes fail.

So, we will use combination here .

No. of ways can 2 or 3 nodes fail= $^{60}{C_2 +^{60}C_3$

Formula : $^nC_r =\frac{n!}{r!(n-r)!}$

No. of ways can 2 or 3 nodes fail= $\frac{60!}{2!(60-2)!}+\frac{60!}{3!(60-3)!}$

= $35990$

Hence there are 35990 ways in which 2 or 3 nodes fail

5 0

3 years ago