Answer:
-6
Step-by-step explanation:
Answer:
Step-by-step explanation:
1. a). Hypotenuse² = (Leg 1)² + (Leg 2)²
h² = 10² + 24²
h = √676
h = 26
(b). Hypotenuse² = (Leg 1)² + (Leg 2)²
(25)² = (15)² + (leg 2)²
Leg 2 = √(625 - 225)
= √400
= 20
(c). Hypotenuse² = (Leg 1)² + (Leg 2)²
h² = 4² + 6²
h = √(16 + 36)
h = √52
h = 2√13
(d). Hypotenuse² = (Leg 1)² + (Leg 2)²
(14)² = (Leg 1)² + 7²
Leg 1 = √(196 - 49)
= √147
= 7√3
2). Hypotenuse² = (Leg 1)² + (Leg 2)²
Leg 1 = leg 2 = 7 units [Since, triangle is an isosceles triangle]
h² = 7² + 7²
h = √98
h = 7√2
Option (1) is the correct option.
3). Hypotenuse² = (Leg 1)² + (Leg 2)²
(26)² = (Leg 1)² + (10)²
Leg 1 = √(676 - 100) = 24
Area of a right triangle = 
= 
= 120 square units
Option (3) is the correct option.
Given :
Price per folder = $2.15 .
Price per notebook = $4.60 .
The supply budget for this meeting is $150.
To Find :
Inequality represents the constraint on the number of folders f and notebooks n the office administrator can purchase.
Solution :
Let, number of folders and notebooks is f and n.
So, price of buying f and n number of folders and notebooks are :
P = 2.15f + 4.60n
Now, it is given that P ≤ $150 .
So,
2.15f + 4.60n ≤ 150
Hence, this is the required solution.
Cool I guess I’m getting none