Answer:
Speed of plane in air is 352 km/hr and speed of wind is 34 km/hr
Step-by-step explanation:
Average speed of plane in with wind = 386 km/h
Average speed of plane against wind = 318 km/hr
Consider the speed of plane in wind be x km/hr and speed of plane against wind be y km/hr
As such speed of plane in wind would be x + y km/hr and speed of plane against wind would be x - y km/hr. i.e
x+y = 386
x-y = 318
by solving these two equation, we get
2x=704
x= 352 km/hr
y=386 - 352
y= 34 km/hr
Hence, Speed of plane in air is 352 km/hr and speed of wind is 34 km/hr
Answer:
It's a tie!
Step-by-step explanation:
The reason it was a tie is because
56/98 = 0.57 meaning that 57% of Restaurant A won
84/147 = 0.57 meaning that 57% of Restaurant B also won!
You're going to use the substitution method for this.
First, we know that Y = x-7, so we can plug x-7 into everywhere we see Y!
3x - 3(x - 7) = 21
then we simplify
3x - 3x + 21 = 21
^ ^
These cancel out!
So we're left with...
21 = 21
That means that the solution to this equation is all real numbers!
Y = -X + 7
Y = .5(X-3)2
Alright check it out. Substitute the Y in the second equation for the first equation so...
-X + 7 = .5(X-3)2
After this, you have to get rid of the .5 and the 2 which is easy peasy because they just cancel out. If you were to multiply by half and then multiply by 2 then you'd be back to where you started. So...
-X + 7 = X - 3
Move the X to combine them on one side, I moved the -X to the opposite side by adding X to each side so you get...
7 = 2X - 3
You then add 3 to both side so...
10 = 2X
Divide by 2
X = 5
So...
Y = -5 + 7
Y = 2
Y = .5(5-3)2
Cancel out the .5 and the 2
Y = 5-3
Y = 2
(5,2) is your answer
Answer:

Step-by-step explanation:
Step 1:-
using logarithmic formula 
so given 
now simplify
= 
<u>Answer:</u>-
![log(x^{3}y^{2})= [tex]3 log x+2 log y](https://tex.z-dn.net/?f=log%28x%5E%7B3%7Dy%5E%7B2%7D%29%3D%20%5Btex%5D3%20log%20x%2B2%20log%20y)