1/6×2/3 show me how to do it

Solve for the missing side round to the nearest 10th (look at image)

SIZIF [17.4K]

Answer:

14.3

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

14^2 + 3^2 = c^2

196 + 9 = c^2

205 = c^2

Take the square root of each side

sqrt(205) = sqrt(c^2)

14.31782106 = c

Rounding to the nearest tenth

14.3 = c

3 0

2 years ago

Read 2 more answers

Write two different rational functions whose graphs have the same end behaviour as the graph of y=3x^2

baherus [9]

Answer:

$y=x^2+5x+20\\ \\ y=8x^2+35$

Explanation:

The end behavior of a rational function is the limit of the function as x approaches negative infinity and infinity.

Note that the the values of even functions are the same for ± x. That implies that their limits for ± ∞ are equal.

The limits of the quadratic function of general form $y=ax^2+bx+c$ as x approaches negative infinity or infinity, when $a$ is positive, are infinity.

That is because as the absolute value of x gets bigger y becomes bigger too.

In mathematical symbols, that is:

$\lim_{x \to -\infty}3x^2=\infty\\ \\ \lim_{x \to \infty}3x^2=\infty$

Hence, the graphs of any quadratic function with positive coefficient of the quadratic term will have the same end behavior as the graph of y = 3x².

Two examples are:

$y=x^2+5x+20\\ \\ y=8x^2+35$

5 0

3 years ago

What is the value of the function f left parenthesis x right parenthesis equals 20 x when x equals 0.25?

masya89 [10]

Answer:

Step-by-step explanation:

7 0

3 years ago

The average weight of the entire batch of the boxes of cereal filled today was 20.5 ounces. A random sample of four boxes was se

zhenek [66]

Answer:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s= 0.286$

And then the estimator for the standard error is given by:

$SE= \frac{0.286}{\sqrt{4}}= 0.143$

Step-by-step explanation:

For this case we have the following dataset given:

20.05, 20.56, 20.72, and 20.43

We can assume that the distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for this case would be:

$SE= \frac{\sigma}{\sqrt{n}}$

And we can estimate the deviation with the sample deviation:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s= 0.286$

And then the estimator for the standard error is given by:

$SE= \frac{0.286}{\sqrt{4}}= 0.143$

4 0

3 years ago

A customer states that she was shorted in change by receiving only 23 cents change from $3.00

Artemon [7]

Answer:

First, I would check and see if she was correct. If she wasnt, I would simply show her why she was incorrect. If I was to accidently short her, I would give her the money and move on with my day. if she refused to leave after showing her that I gave her the correct amount of money, she would probably call for the manager. I'd get the manager, explain what happened, and the annoying customer would most likely get kicked out of the store.

(P.S: sorry if it was a little confusing lol)

8 0

2 years ago