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3 years ago

6

zuri bought 8 cupcakes,16chocolate cookies and five peanut butter cookies.How many more cookies will need to buy if he wants 2 d

ozen cookies

1 answer:

shtirl [24]3 years ago

6 0

She will need to buy 3 more cookies because 2 dozens is 24. And 16 cookies plus 5 is 21 cookies plus 3 is a dozen cookies which is 24

24=16 chocolate cookies+5 peanut cookies+3 random cookies

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Consider an urn containing 8 white balls, 7 red balls and 5 black balls.

weqwewe [10]

Answer + Step-by-step explanation:

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$=C^{2}_{5}\times (\frac{8}{20} \times \frac{7}{19}) \times (\frac{12}{18} \times \frac{11}{17} \times \frac{10}{16})\\=0.397316821465$

3) The probability of getting at least 72 white balls is:

$=C^{72}_{150}\times \left( \frac{8}{20} \right)^{72} \times \left( \frac{7}{20} \right)^{78} +C^{73}_{150}\times \left( \frac{8}{20} \right)^{73} \times \left( \frac{7}{20} \right)^{77} + \cdots +C^{149}_{150}\times \left( \frac{8}{20} \right)^{149} \times \left( \frac{7}{20} \right)^{1} +\left( \frac{8}{20} \right)^{150}$

$=\sum^{150}_{k=72} [C^{k}_{150}\times \left( \frac{8}{15} \right)^{k} \times \left( \frac{7}{15} \right)^{150-k}]$

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9 months ago

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pickupchik [31]

<span>twice the sum of a number and seven is 8
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ziro4ka [17]

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