All categories

3 years ago

Can anyone help me with this math test I got to get it turned in by midnight tonight so please respond quick!!

Mathematics

2 answers:

Sergio039 [100]3 years ago

8 0

Answer:

The answer is C.

Step-by-step explanation:

You first have to take 50 and divide it by 3 to get 16.6 repeating. From there, you just have to turn it into a fraction which would be between 1 half and 3 fourths.

frutty [35]3 years ago

8 0

Answer:

Step-by-step explanation:

50 ÷ 3 = 16.67

½ = 0.5

¾ = 0.75

So, the answer is C ^^

You might be interested in

This is my last question please help !

chubhunter [2.5K]

Answer:

try the third option

Step-by-step explanation:

At least I'm trying

8 0

3 years ago

Px + qy = r<br> 2px - qy = 2r<br> When solving this system of equations, x =

VladimirAG [237]

Px + qy = r
2px - qy = 2r
----------------add
3px = 3r

x = 3r/3p
x = r/p

8 0

4 years ago

Read 2 more answers

The circumference of Circle F is 72 cm. What is the length of Arc DE (the minor arc)?

Tom [10]

You need to first set up the equation:

It would look like 90 divided by 360 multiplied by the given circumference which is 72 cm.

So 90 / 360 x 72

Simply the fraction above, it will give us:

¼ x 72

So the answer would be 18 cm that is the length of DE (minor arc)

4 0

4 years ago

Read 2 more answers

Which of the following is a solution of z^5 = 1 + √3 i?

nordsb [41]

Answer:

Option 2 is right

Step-by-step explanation:

Given that

$z^5=1+\sqrt{3} i$

We can write this in polar form with modulus and radius

$|z^5|= \sqrt{1+3} =2\\tan of Angle t =\sqrt{3} \\$

Hence angle = 60 degrees and

$|z^5|= 2(cos60+isin60)$

Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360

Using Demoivre theorem we get 5th root would be

5th root of 2 multiplied by 1/5 th of 60, 420, 780,....

$z= \sqrt[5]{2} (cos12+isin12)\\z=\sqrt[5]{2} (cos84+isin84)\\\\z=\sqrt[5]{2} (cos156+isin156)\\\\z=\sqrt[5]{2} (cos228+isin228)\\\\z=\sqrt[5]{2} (cos300+isin300)\\$

Out of these only 2nd option suits our answer

Hence answer is Option 2.

8 0

3 years ago

A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?

seraphim [82]

Answer:

$P\left(E\right)=\frac{55}{1024}$

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

$nCr=\frac{n!}{r!\left(n-r\right)!}$