C(x) = 400 + 20x - 0.2x²
c(30) = 400 + 20(30) - 0.2(30)²
= 400 + 600 - 0.2(900)
= 1000 - 180
= 820
It costs $820 when 30 radios are produced.
Marginal cost is how much it would cost to make one MORE of the same product so now we find how much it costs to produce 31 radios and compare the two.
c(31) = 400 + 20(31) - 0.2(31)²
= 400 + 620 - 0.2(961)
= 1020 - 192.2
= 827.8 or ≈828.
Now we find the difference which means we subtract the two.
828 - 820 = 8.
Your marginal cost is $8.
To compare we can also do 29 radios.
c(29) = 400 + 20(29) - 0.2(29)² = 811.8 or ≈812
820 - 812 = 8.
Okay, think of it this way:
You have to find how many times 4,000 goes into 150,000.
This will tell you how many costumes you can buy.
To make this easier, we can divide 4 by 150. (this is proportional to 4,000 and 150,000 since we took 3 zeros from each number; you will get the same answer)
150/4= 37.5
You can buy 37 whole costumes.
Hope this helped!
1. 9/15 and 10/15
2. 7/9 and 6/9
3. 16/24 and 3/24
4. 3/12 and 8/12
5. 25/30 and 18/30
<h3><u>Answer:</u></h3>
<h3>
<u>Solution:</u></h3>
We are given that the arithmetic progression is defined by :
➝ 2n + 1
<em>Therefore, </em>
- <u>For </u><u>first </u><u>term</u>
➙ n = 1
➝ 2 × 1 + 1
➝ 2 + 1
➝ 3
- <u>For </u><u>second </u><u>term</u>
➙ n = 2
➝ 2 × 2 + 1
➝ 4 + 1
➝ 5
- <u>Common </u><u>difference</u>
➙ 2nd term - 1st term
➝ 5 - 3
➝ 2
<h3><u>More </u><u>information</u><u>:</u></h3>
- The difference between the successive term and the preceding term is the difference of an arithmetic progression. It is always same for the same arithmetic progression.
