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garik1379 [7]
3 years ago
7

Which of the following is the equation of the x-axis?​

Mathematics
2 answers:
STALIN [3.7K]3 years ago
6 0
1 is the axis that’s the answer
pickupchik [31]3 years ago
4 0

Answer:

1

Step-by-step explanation:

x=0 so 0+1 equals 1

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Find the 8th term in the sequence: x + 1, 2x + 1, 3x + 1,...
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The common difference is x

the first term is x+1

a_8 = x+1 + x(8-1) = x+1 + 7x = 8x + 1

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2 years ago
Hanna has 44 minutes to get ready for school she spends x minutes getting dress what's an expression that represent the number o
Goshia [24]
44-x= amount of time left
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3 years ago
Working alone and at a constant rate, Machine A takes 3 hours to create a widget. Machine B, working alone and at a constant rat
PilotLPTM [1.2K]

Answer:

Time required by Machine B to create a widget = 4 hours

Step-by-step explanation:

Time taken by Machine A ( T_{A} ) = 3 hours

Time taken by Machine B ( T_{B} )= x hours

Time taken by both machines by working together = 12 hours

The time required to both machines by  working together to finish a task is given by the formula = \frac{T_{A} {T_{B} } }{T_{A} + T_{B} }

Put the values in above formula we get

⇒ T =  \frac{3 x}{3 + x}

⇒ 12 =  \frac{3 x}{3 + x}

⇒ 36 + 12 x = 3 x

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This is the time required by Machine B to create a widget.

8 0
3 years ago
If a polynomial function f(x) has roots 3+
irinina [24]

Answer:

Step-by-step explanation:

3+√5 is a root.

so 3-√5 is also a root

or (x-(3-√5)) is also a factor of f(x)

7 0
2 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
1 year ago
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