Answer:
No
Step-by-step explanation:
An extraneous solution is a root of a transformed equation which is not a root of the original equation because it was not included in the domain of the original equation.
Ahmed is solving ![2\sqrt[3]{x-7}+11=3](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7Bx-7%7D%2B11%3D3)
for x.
His steps were:
![\begin{aligned}2\sqrt[3]{x-7}&=-8\\ \sqrt[3]{x-7}&=-4\\ \left(\sqrt[3]{x-7}\right)^3&=(-4)^3\\ x-7&=-64 \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D2%5Csqrt%5B3%5D%7Bx-7%7D%26%3D-8%5C%5C%20%20%5Csqrt%5B3%5D%7Bx-7%7D%26%3D-4%5C%5C%20%20%5Cleft%28%5Csqrt%5B3%5D%7Bx-7%7D%5Cright%29%5E3%26%3D%28-4%29%5E3%5C%5C%20%20x-7%26%3D-64%20%5Cend%7Baligned%7D)
Since cube roots <u>do not give two solutions when solved</u>, it is <u>not necessary </u>to check his answers for extraneous solutions.
The correct answer would be B.
Answer:
12
Step-by-step explanation:
To have an even integer the number's endian has to be an even number. Consider the 2-digit positive number like _ _ and place the number of possible options out of four total options in each blank space. We have 3 even options, so we can fill the endian blank like this _ <u>3</u>
Since the first digit can be any number, therefor, we have 4 options for the first blank space <u>4</u> <u>3</u>. Just multiply the two numbers and you have the answer.
22, 24, 28, 42, 44, 48, 52, 54, 58, 82, 84, 88
the length is given and i got the width as 8 so you just add up all the sides and i got 40
