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Oxana [17]
3 years ago
15

Suppose that a is a nonzero constant for which the equation ax^2+20x+7=0 has only one solution. find this solution.

Mathematics
1 answer:
Talja [164]3 years ago
4 0
\Delta=0\\\\
\Delta=20^2-4\cdot a\cdot7=400-28a\\
400-28a=0\\
28a=400\\
a=\dfrac{400}{28}=\dfrac{100}{7}


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