Answer B. since it has 5x^4
For part 8-71,
a) 2=105
b) 2=55
c) 2=53
d)2=160
Answer: 4(3+1)/4c-q^1/2d i think tht is how you do it...
Step-by-step explanation:
apply the distribuitive property to create an equivalent expression
4
(
3
+
1
)
4
c
−
q
1
2
d
Write the problem as a mathematical expression.
apply the distribuitive property to create an equivalent expression
4
(
3
+
1
)
4
c
−
q
1
2
d
Simplify.
4
(
3
+
1
)
4
c
−
q
2
d
Add
3
and
1
.
4
⋅
4
4
c
−
q
2
d
Simplify the denominator.
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4
⋅
4
8
c
d
−
q
2
d
Multiply
4
by
4
.
16
8
c
d
−
q
2
d
Multiply the numerator by the reciprocal of the denominator.
16
2
d
8
c
d
−
q
Multiply
16
2
d
8
c
d
−
q
.
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32
d
8
c
d
−
q
Answer: the probability that a truck drives between 166 and 177 miles in a day is 0.0187
Step-by-step explanation:
Since mileage of trucks per day is distributed normally, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = mileage of truck
µ = mean mileage
σ = standard deviation
From the information given,
µ = 100 miles per day
σ = 37 miles miles per day
The probability that a truck drives between 166 and 177 miles in a day is expressed as
P(166 ≤ x ≤ 177)
For x = 166
z = (166 - 100)/37 = 1.78
Looking at the normal distribution table, the probability corresponding to the z score is 0.9625
For x = 177
z = (177 - 100)/37 = 2.08
Looking at the normal distribution table, the probability corresponding to the z score is 0.9812
Therefore,
P(166 ≤ x ≤ 177) = 0.9812 - 0.9625 = 0.0187
Just move all terms to the left side and set equal to zero. Then, set each factor equal to zero.
a = 5,1
