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3 years ago

Which linear inequality is represented by the graph?

Mathematics

1 answer:

Vesnalui [34]3 years ago

3 0

Do u have a pic of the problem?

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Kendra gets a paycheck of $300 after 5 days of work.At this rate,how much does she get paid for working 24 days?

Misha Larkins [42]

answer : $1440 i believe.

5 0

3 years ago

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If nine times a certain number is subtracted from 7 the result is 52. Find the number.

mezya [45]

Answer:

Let the number to find be x

7 - 9x = 52

-9x = 52-7

- 9x = -45

Divide by - 9

x = 5

The number is 5

Hope this helps.

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3 years ago

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7.5% of the grade has green eyes if there are 120 students in the grade how many dont have green eyes

GREYUIT [131]

Answer:

Step-by-step explanation:

If 7.5 % has green eyes, then 92.5% (the complement given by 100%-7.5%) dont have green eyes. 92.5% of 120 is given by

0.925*(120)=111

111 students in the grade dont have green eyes.

8 0

3 years ago

What is the roots of the quadratic equation? 6x^2+5x-4=0

Rama09 [41]

x = $\frac{1}{2}$ or x = - $\frac{4}{3}$

consider the factors of the product 6 × - 4 = - 24 which sum to the coefficient of the x- term ( + 5)

the factors are + 8 and - 3 ( split the middle term using these factors

6x² - 3x + 8x - 4 = 0 ( factor by grouping )

3x(2x - 1) + 4(2x - 1 ) ( take out common factor of (2x - 1) )

= (2x - 1)(3x + 4) = 0

equate each factor to zero and solve for x

2x - 1 = 0 ⇒ x = $\frac{1}{2}$

3x + 4 = 0 ⇒ x = - $\frac{4}{3}$

4 0

3 years ago

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If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago