Which linear inequality is represented by the graph?

Classify the following triangle. Check all that apply

kramer

D and E. If I remember right that should be the answer.

7 0

3 years ago

7. A battery manufacturer makes batteries that have a failure rate of .015. That is, 15 out of each 1,000 batteries are defectiv

azamat

The answer to this probability question is .86 or 86%. The probability that a batch of 10,000 batteries will contain at least 175 defective batteries is 86 percent. I calculated the failure rate of 10,000 batteries (10k*.015) and yielded 150, meaning there will be 150 batteries that will be defective in a set of 10,000. Then i divided 150 by 175 to get the probability.

3 0

3 years ago

Simplify each expression using an exponent rule learned in class. <img src="https://tex.z-dn.net/?f=%28%5Cfrac%7By%7D%7Bx%7D%20%

Maksim231197 [3]

Hey there! I'm happy to help!

If you raise a fraction to an exponent, you apply that exponent to the numerator and the denominator. This would give us $\frac{y^4}{x^4}$ .

Have a wonderful day! :D

3 0

3 years ago

Read 2 more answers

Which statement is not true for a binomial distribution with n = 15 and p = 1/20 ? a) The standard deviation is 0.8441 b) The nu

malfutka [58]

Answer:

d) The highest probability occurs when x equals 0.7500

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability, given by the following formula:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

In this problem, we have that:

$n = 15, p = \frac{1}{20}$

a) The standard deviation is 0.8441

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15*0.05*0.95} = 0.8441$

This is correct

b) The number of trials is equal to 15

n is the number of trials and $n = 15$ . So this option is correct.

c) The probability that x equals 1 is 0.3658

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{15,1}.(0.05)^{1}.(0.95)^{14} = 0.3658$

This option is correct.

d) The highest probability occurs when x equals 0.7500

False. The number of sucesses is a discrete number, that is, 0, 1, 2,...,15. P(X = 0.75), for example, does not exist.

e) The mean equals 0.7500

$E(X) = np = 15*0.05 = 0.75$

This option is correct.

f) None of the above

d is false

3 0

3 years ago

What is the value of log 7 343?–3 -1/3 1/3 3

xeze [42]

Answer: 3

Step-by-step explanation:

Given :

$Log_{7}$ 343

We need to write 343 in index form of 7.

343 is the same as $7^{3}$ , replacing 343 with $7^{3}$ , we have

$Log_{7}$ $7^{3}$

Recall one on the law of Logarithm :

$Log_{a}$ $b^{c}$ can be written as c $Log_{a}$ b

So, $Log_{7}$ $7^{3}$ can be written as ;

3 $Log_{7}$ 7

Also from the laws of Logarithms , $Log_{a}$ a = 1

so , Log_{7}[/tex] 7 = 1

The solution then becomes

3 x 1 = 3

Therefore :

$Log_{7}$ 343 = 3

8 0

3 years ago