Answer:
Step-by-step explanation:
Part A:
C = 10t + s
Part B:
10(3) + 8
30 + 8 = $38
Answer:
∠ EFG = 83°, ∠ GCE = 97°
Step-by-step explanation:
Since FE and FG are tangents to the circle then
∠ FGC and ∠ FEC are right angles
The sum of the angles in quadrilateral CEFG = 360°
Sum the 4 angles and equate to 360
3x + 11 + 90 + 5x - 23 + 90 = 360, that is
8x + 168 = 360 ( subtract 168 from both sides )
8x = 192 ( divide both sides by 8 )
x = 24
Thus
∠ EFG = 3x + 11 = 3(24) + 11 = 72 + 11 = 83°
∠ GCE = 5x - 23 = 5(24) - 23 = 120 - 23 = 97°
After the expression is simplified as much as possible, x is raised to the exponent 2
Hello,
If center is (0,0)
x²/a²+y²/b²=1 for a half horizontal axis of a, and a half vertical axis of b
Here
a=2 ==> a²=4
b=8 ==> b²=64
Let 
be the weight of i-th player.
1. If the mean weight of 4 backfield members on the football team is 221 lb, then
2. If the mean weight of the 7 other players is 202 lb, then
3. From the previous statements you have that
Add these two equalities and then divide by 11:
Answer: the mean weight of the 11-person team is 
