The answer is C, the function is not following constant change, so not linear, and if it was .1^x, then it would be 1.4 instead of 12.6. So C is correct.
Answer:
54.72 months
Step-by-step explanation:
Given:
Future value = R35,000
Annuity = R500
Interest = 11.32% per year
Interest per month, r = 
= 0.943% = 0.00943
Let 'n' be the total time in months taken
Now,
Future value of annuity is calculated using the formula as:
![\textup{Future value}=\textup{Annuity}\times[\frac{(1+r)^n-1}{r}]](https://tex.z-dn.net/?f=%5Ctextup%7BFuture%20value%7D%3D%5Ctextup%7BAnnuity%7D%5Ctimes%5B%5Cfrac%7B%281%2Br%29%5En-1%7D%7Br%7D%5D)
on substituting the respective values, we get
![35000=500\times[\frac{(1+0.00943)^n-1}{0.00943}]](https://tex.z-dn.net/?f=35000%3D500%5Ctimes%5B%5Cfrac%7B%281%2B0.00943%29%5En-1%7D%7B0.00943%7D%5D)
or
![70=[\frac{(1.00943)^n-1}{0.00943}]](https://tex.z-dn.net/?f=70%3D%5B%5Cfrac%7B%281.00943%29%5En-1%7D%7B0.00943%7D%5D)
or
1.6601 = 1.00943ⁿ
taking log both sides, we get
log(1.6601) = n × log(1.00943)
or
0.22= n × 0.00402
or
n = 54.72 months
Answer:
<em>b = 28</em>
Step-by-step explanation:
b + 28 = 2b
28 = 2b - b
28 = b
b = 28
I believe the answer is B
Answer:y = x 2 − 12 x The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined. Interval Notation: ( − ∞ , ∞ ) Set-Builder Notation: { x | x ∈ R } The range is the set of all valid y values. Use the graph to find the range. Interval Notation: [ − 36 , ∞ ) Set-Builder Notation: { y | y ≥ − 36 } Determine the domain and range. Domain: ( − ∞ , ∞ ) , { x | x ∈ R } Range: [ − 36 , ∞ ) , { y | y ≥ − 36 }
Step-by-step explanation:
