Answer:
Step-by-step explanation:
From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e () and are parallel to
The parallel vector to the line i + zj+k = ai + bj + ck
Hence, the equation for the line is :
x = 4 + t
y = -5 + 2t
z = 2 + t
Thus, x, y, z = ( 4+t, -5+2t, 2+t )
The symmetric equation can now be as follows:
∴
Answer:
A
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
To calculate m use the slope formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (1, 6) and (x₂, y₂ ) = (2, 1)
m = = - 5, hence
y = - 5x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (1, 6), then
6 = - 5 + c ⇒ c = 6 + 5 = 11
y = - 5x + 11 → A