Given, IJ = 3x + 3, HI = 3x - 1, and HJ = 3x + 8.
Since I is a point on line segment HJ, we can write


Put x=2 in HJ=3x+8.

Therefore, the numerical length of HJ is 14.
<span>x^2 = 81
x = </span>±√81
x = ±9<span>
x^2 = -9 no solutions
x^2 = 20
x = </span>±√20
x = <span>±2</span>√5<span>
</span>

<span>
</span>
Answer: I think it's D
Step-by-step explanation:
Answer:
Part 22) The area is
and the perimeter is 
Part 24) The area is
and the perimeter is
Part 26) The area is equal to 
Step-by-step explanation:
Part 22) Find the perimeter and area
step 1
The area of a rectangle is equal to

we have


Remember that
When multiply exponents with the same base, adds the exponents and maintain the base
substitute in the formula


step 2
The perimeter of a rectangle is equal to

we have

substitute in the formula


Part 24) Find the perimeter and area
step 1
The area of triangle is equal to

where


Remember that
When multiply exponents with the same base, adds the exponents and maintain the base
substitute the given values


step 2
Find the perimeter
I will assume that is an equilateral triangle (has three equal length sides)
The perimeter of an equilateral triangle is

where

substitute


Part 26) Find the area
The area of a circle is equal to

where

Remember the property

substitute in the formula the given value


Answer:
j = 5
Step-by-step explanation:
16j + -6j + -12j = -10
Combine like terms
10j -12j = -10
-2j = -10
Divide by -2
-2j/-2 = -10/-2
j = 5