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Fudgin [204]
3 years ago
13

Find the probability P(z < 0.37) using the standard normal distribution.

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

0.6443

Step-by-step explanation:

Given the that:

P(Z < 0.37) ; using a standard normal distribution :

The probability can be obtained using several methods :

Using a standard normal distribution table ;

P(Z < 0.37) = obtain the value at the intersection where 0.3 is on the vertical axis and 0.07 on the horizontal axis of the Z distribution table

Hence,

P(Z < 0.37) = 0.6443

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How are the solutions to the following two equations related m+5=72 <br> m+72=5
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To see how they are related, let us solve the two equations.

FIRST EQUATION

m + 5 = 72

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SECOND EQUATION

m + 72 = 5

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Hence the solutions to the two equations are ADDITIVE INVERSE of each other.
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4 years ago
The length of a field in yards is a function f( n ) of the the length in n feet. Write a function rule for this situation.
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3 years ago
What fraction is greater than 4/5
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4 years ago
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

5 0
3 years ago
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