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frez [133]
3 years ago
12

It costs $50 plus $28 per month to join the gym.How much would it cost to join for 7 months?​

Mathematics
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

$546

Step-by-step explanation:

50 + 28 = 78 x 7 = 546

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krok68 [10]
The answer is 300 divided by 20 which you would get 15.
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3 years ago
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John has 50 missing assignments in his history and science class. He only has 15 days to turn everything in. How many assignment
Nadusha1986 [10]

Answer:

3.3333 (repeating)

Step-by-step explanation:

He has 50 missing assignments and 15 days to do them.

So you do 50 missing assignments divided by 15 days, to see how many assignments a day he would have to do.

50 / 15 = 3.33 (repeating)

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3 years ago
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A crew will arrive in one week and begin filming a city for a movie. The mayor is desperate to clean the city streets before fil
Tatiana [17]

Answer:

I think you would add the numbers then divide by 2

Step-by-step explanation:

8 0
3 years ago
Diego is collecting dimes and nickels in a jar. He has collected $22.25 so far. The relationship between the numbers of dimes an
svet-max [94.6K]

Answer:

Correct options are:

a) ( 0 , 445 )

d) ( 118 , 209 )

e) ( 172 , 101 )

Step-by-step explanation:

A nickel is worth 5 cents $0.05

A dime is worth 10 cents = $0.10

The relationship between the numbers of dimes and nickels, and the amount of money in dollars is represented by the equation 0.10d+0.05n=22.25. Select the THREE values (d,n) that could be solutions to the equation.

a) ( 0 , 445 )

b) ( 0.50 , 435 )

c) ( 233 , 21 )

d)( 118 , 209 )

e)( 172 , 101 )

Verifying the options

a) ( 0 , 445 )

0.10d+0.05n=22.25.

= 0.10(0) + 0.05(445) = 22.25

= 22.25 = 22.25

Options a) is correct

b) ( 0.50 , 435 )

0.10d+0.05n=22.25.

= 0.10(0.50) + 0.05(435) = 22.25

= 21.8 ≠ 22.25

Option b is incorrect

c) ( 233 , 21 )

0.10d+0.05n=22.25.

= 0.10(233) + 0.05(21) = 22.25

= 24.35 ≠22.25

Option c is incorrect

d) ( 118 , 209 )

0.10d+0.05n=22.25.

= 0.10(118) + 0.05(209) = 22.25

= 22.25 = 22.25

Option d) is correct

e) ( 172 , 101 )

0.10d+0.05n=22.25.

= 0.10(172) + 0.05(101) = 22.25

= 22.25 = 22.25

Option e) is correct

5 0
3 years ago
Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

5 0
3 years ago
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