Answer:
Probability that the measure of a segment is greater than 3 = 0.6
Step-by-step explanation:
From the given attachment,
AB ≅ BC, AC ≅ CD and AD = 12
Therefore, AC ≅ CD = 
= 6 units
Since AC ≅ CD
AB + BC ≅ CD
2(AB) = 6
AB = 3 units
Now we have measurements of the segments as,
AB = BC = 3 units
AC = CD = 6 units
AD = 12 units
Total number of segments = 5
Length of segments more than 3 = 3
Probability to pick a segment measuring greater than 3,
= 
= 
= 0.6
So it is really easy to solve firstly we can see how much does the first 10 boxes make which makes around 55$ obviously. Secondly 45$ for the next 10 boxes.
So for now we can simply calculate that we have spent around 100$ which means 20 boxes. The remaining money left is 77$ so we can buy 77/3.5 = 22 only 22 boxes with that money. Hence a total of 42 boxes.
Answer:x= -3/8
Step-by-step explanation: