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zhuklara [117]
3 years ago
10

A quadratic function has one zero (x-intercept) at x = -5 and another zero at x = 3. What is the equation of the axis of symmetr

y of this function?
Mathematics
1 answer:
liraira [26]3 years ago
8 0

Answer:

x = - 1

Step-by-step explanation:

The axis of symmetry is a vertical line located at the midpoint of the zeros.

Equation is then

x = \frac{-5+3}{2} = \frac{-2}{2} = - 1 , that is x = - 1

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Answer:

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The sum of -6 times a number x and 9 is at least 27. what are the possible values of the number​
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3 years ago
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777dan777 [17]

Answer:

  • (x + 10)² + (y + 4)² = 232

Step-by-step explanation:

<h3>Given </h3>
  • Center = (-10, -4)
  • Point on circle = (4, 2)
<h3>To find </h3>
  • The equation of circle
<h3>Solution</h3>

<u>Remember the standard equation of circle:</u>

  • (x - h)² + (y - k)² = r², where (h, k) is the center and r is radius

<u>We have</u>

  • h = -10, k = -4

Use distance formula (Pythagorean theorem) to work out the length of the radius. We know that radius is the distance from the center to any point on the circle.

<u>Here we are finding the distance between points (-10, -4) and (4, 2)</u>

  • r² = (-10 - 4)² + (-4 - 2)²
  • r² = 14² + 6²
  • r² = 232

<u>So the equation is:</u>

  • (x + 10)² + (y + 4)² = 232
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3 years ago
A variable needs to be eliminated to solve the system of equations below. Choose the
notsponge [240]

Answer:

x=-2

y= 8

Step-by-step explanation:

Given data

10x – 2y = -36-----------1

7x – 2y = -30--------------2

-Subtract to eliminate y

3x-0= -6

3x= -6

x= -6/3

x= -2

Put x= -2 in

7(-2)– 2y = -30

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-14+30=2y

16=2y

y= 16/2

y= 8

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