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Serga [27]
3 years ago
15

What is the measure of angle c​

Mathematics
1 answer:
irakobra [83]3 years ago
6 0

Answer:

? wouldn't it be obtuse

Step-by-step explanation:

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Question content area top Part 1 Three friends all live on the same street that runs west to east. lives blocks from . lives fro
Harrizon [31]

Based on the information, it can be inferred that Carl's house is 6 blocks from Ann's house.

<h3>How to identify where each friend's house is?</h3>

To identify where each friend's house is, we must graph the information provided as shown below.

Once we have made the graph we will identify that Carl's house is 6 blocks east of Ann's house.

Note: This question is incomplete because there is some information missing. Here is the missing information:

  • Ben lives 4 blocks from Ann.
  • Carl lives 2 blocks from Ben.
  • Ann​'s house is located at​ 0.

Learn more about location in: brainly.com/question/11718756

#SPJ1

6 0
2 years ago
Find x<br><br> -x = 7x - 56
solmaris [256]

Answer:

the answer is 7

Step-by-step explanation:

Add the same term to both sides of the equation

-x=7x-56

−x=7x−56

−x−7x=7x−56−7x

3 0
3 years ago
Read 2 more answers
The difference between the roots of the equation 2x^2-5x+c=0 is 0.25. Find c.
gogolik [260]
I think u need to add a pic
8 0
3 years ago
N:1/2 as 6:1 PLS HELP<br> x=
kari74 [83]

Answer:

what????

Step-by-step explanation:

8 0
3 years ago
Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t
levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

<u><em>Let X = prices of a certain model of a new home</em></u>

SO, X ~ Normal(\mu=150,000 ,\sigma=2,300)

The z score probability distribution for normal distribution is given by;

                             Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean price = $150,000

            \sigma = standard deviation = $2,300

<u>Now, according to 68-95-99.7 rule;</u>

Around 68% of the values in a normal distribution lies between \mu-\sigma and \mu-\sigma.

Around 95% of the values occur between \mu-2\sigma and \mu+2\sigma .

Around 99.7% of the values occur between \mu-3\sigma and \mu+3\sigma.

So, firstly we will find the z scores for both the values given;

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{147,700-150,000}{2,300}  = -1

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{152,300-150,000}{2,300}  = 1

This indicates that we are in the category of between \mu-\sigma and \mu-\sigma.

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

7 0
4 years ago
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