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2 years ago

I need to find the area of a semicircle with a radius of 2 units

Mathematics

1 answer:

MariettaO [177]2 years ago

5 0

Answer:

6.2832 square units (rounded off to four decimal values)

Step-by-step explanation:

Area of a semicircle = $\frac{1}{2}$ × π × r²

r (radius) = 2 units

For our semicircle the area = $\frac{1}{2}$ × π × 2² = 6.28318530718 square units

Or 6.2832 square units (rounded off to four decimal values)

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I need help with these three problems please

Liono4ka [1.6K]

Answer:

Q7. 11.3 inches (3 s.f.)

Q8. 96.2 ft

Q9. 36.4cm

Step-by-step explanation:

Q7. Please see attached picture for full solution.

Q8. Let the length of a side of the square be x ft.

Applying Pythagoras' Theorem,

$34^{2} = {x}^{2} + {x}^{2} \\ 2 {x}^{2} = 1156 \\ {x}^{2} = 1156 \div 2 \\ {x}^{2} = 578 \\ x = \sqrt{578} \\$

Thus, the perimeter of the square is

$= 4( \sqrt{578} ) \\ = 96.2 ft\: \: \: (3 \: s.f.)$

Q9. Equilateral triangles have 3 equal sides and each interior angle is 60°.

Since the perimeter of the equilateral triangle is 126cm,

length of each side= 126÷3 = 42 cm

The green line drawn in picture 3 is the altitude of the triangle.

Let the altitude of the triangle be x cm.

sin 60°= $\frac{x}{42}$

$\frac{ \sqrt{3} }{2} = \frac{x}{42} \\ x = \frac{ \sqrt{3} }{2} \times 42 \\ x = 21 \sqrt{3} \\ x = 36.4$

(to 3 s.f.)

Therefore, the length of the altitude of the triangle is 36.4cm.

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hope that helps, God bless!

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3 years ago