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Zepler [3.9K]
3 years ago
14

I need to find the area of a semicircle with a radius of 2 units

Mathematics
1 answer:
MariettaO [177]3 years ago
5 0

Answer:

6.2832 square units (rounded off to four decimal values)

Step-by-step explanation:

Area of a semicircle = \frac{1}{2} × π × r²

r (radius) = 2 units

For our semicircle the area = \frac{1}{2} × π × 2² = 6.28318530718  square units

Or 6.2832 square units (rounded off to four decimal values)

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*20 points* Explain two barriers to entry for a new business.
Alex

Answer:

Government regulation, Economies of scale

Step-by-step explanation:

Barriers to entry are obstacles that make it difficult to enter a given market. ...

Government Regulation.

Start-Up Costs.

Technology.

Economies of Scale.

Product Differentiation.

Access to Suppliers and Distribution Channels.

Competitive Response.

3 0
3 years ago
Read 2 more answers
Which number is less than 22,874?
monitta

Answer:

A. 2.18 × 10^4

Step-by-step explanation:

2.18 × 10^4

10^4 = 10000

2.18 × 10000 = 21800 which is less than 22874

3 0
3 years ago
In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha
siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95,  P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0
4 years ago
Suppose you buy 1.25-pound package of ham at $5.20 per pound.How much money did you spend
MA_775_DIABLO [31]
You spent $6.50 on the ham
5 0
3 years ago
Solve the equation.
eimsori [14]

Answer:C

Step-by-step explanation:

6(x+7)=5(x-7)+x

⇔6x+42=5x-35+x

⇔6x-5x-x=-35-42

⇔0x=-77  

4 0
3 years ago
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