Let x and y be inversely related. If x is 5 when y is 6, find y when x is 3.
1 answer:
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Part (a)
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See the attached figure which represents the problem.
So, we can note that there are 3 hours increase from <span>Monday thru Friday
</span>
and 4 hours increase in both of Saturday and Sunday
So, <span>the increase in total hours opened = 3*5 + 4*2 = 23 hours
</span>
<span>======================================================
</span>
<span>Part (b):
</span>
<span>=====
</span>
<span>weekly original payroll $ 385
</span>
Total working of old hours = 9 * 5 + 5 * 2 = 55 hours
so, the hourly payroll = 385/55 = $ 7
<span>Assume the hourly wage will stay the same
</span>
Total working of new hours = 55 + 23 = 78 hours
So, the total weekly pay under the new hours = 78 * 7 = $ 546
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Part (c):
========
The total pay for old hours = $ 385
The total pay for new hours = $ 546
The increase in the total pay = 546 - 385 = $ 161
<span>The percentage increase in total pay =
</span>
=======
See the attached figure which represents the problem.
So, we can note that there are 3 hours increase from <span>Monday thru Friday
</span>
and 4 hours increase in both of Saturday and Sunday
So, <span>the increase in total hours opened = 3*5 + 4*2 = 23 hours
</span>
<span>======================================================
</span>
<span>Part (b):
</span>
<span>=====
</span>
<span>weekly original payroll $ 385
</span>
Total working of old hours = 9 * 5 + 5 * 2 = 55 hours
so, the hourly payroll = 385/55 = $ 7
<span>Assume the hourly wage will stay the same
</span>
Total working of new hours = 55 + 23 = 78 hours
So, the total weekly pay under the new hours = 78 * 7 = $ 546
=====================================================
Part (c):
========
The total pay for old hours = $ 385
The total pay for new hours = $ 546
The increase in the total pay = 546 - 385 = $ 161
<span>The percentage increase in total pay =
Answer:
Step-by-step explanation: To find a nonlinear equation, the degree of the linear equation must be 0 or 1 each from its variables.
As we see here the degree of the variable is 1, so y is 1. But the degree of the variables in the equation violates the linear equation definition. Since it does that, it's not counted as a linear equation.
Therefore, is not a linear equation.