I think the answer would be 30 minutes
the answer is 1/8. I double checked
Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2
and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>
The cross product n1 x n2
vl=
i j l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>
By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.
Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t
Michelle's result shows f(2) = -13, selection C.
1. Add 5 to both sides
k/3 = 34 + 5
2. Simplify 34 + 5 to 39
k/3 = 39
3. Multiply both side by 3
k = 39 * 3
4. Simplify 39 * 3 to 117
k = 117