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IRISSAK [1]
3 years ago
15

Determine all values of k that make each of the following a perfect square trinomial. X^2+8x+k

Mathematics
1 answer:
-Dominant- [34]3 years ago
6 0

Answer:

k can either be

12

or

−

12

.

Step-by-step explanation:

Consider the equation

0=x2+4x+4

. We can solve this by factoring as a perfect square trinomial, so

0=(x+2)2→x=−2 and−2

. Hence, there will be two identical solutions.

The discriminant of the quadratic equation (b2−4ac) can be used to determine the number and the type of solutions. Since a quadratic equations roots are in fact its x intercepts, and a perfect square trinomial will have

2 equal, or 1

distinct solution, the vertex lies on the x axis. We can set the discriminant to 0 and solve:

k2−(4×1×36)=0

k2−144=0

(k+12)(k−12)=0

k=±12

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S+2t=6. 3s-2t=2<br> Using elimination
Ludmilka [50]
For the first one, I will solve for t.
s + 2t = 6, first we isolate the t variable,
2t = -s + 6, divide both sides by 2,
t = -s/2 + 3, < There's your answer for 1!

Here's the second one,
3s - 2t = 2, subtract 3s from both sides,
-2t = 2 - 3s, divide both sides by -2,
t = -1 + 3s/2 < There's your second answer!
6 0
3 years ago
72 greater than r is less than −432
pshichka [43]

its Greater than

Step-by-step explanation:

the 72 is a positive and -432 is a negative cause it has a minus

6 0
3 years ago
Write 7:30 in two ways pertaining to time
Vanyuwa [196]
Seven-thirty.
A half an hour past seven o'clock.
4 0
3 years ago
Read 2 more answers
Please Please help me
Inessa [10]

Answer:

1. 30

Step-by-step explanation:

First, place the numbers from least to greatest.

11,13,23,37,45,58

Then, find the middle number (or two middle numbers).

In this case, the middle numbers are 23 and 37.

Third, we find the mean of these numbers.

23+37=60

60/2=30

So your answer is 30.

Repeat this method for the other problems.

4 0
3 years ago
Solve<br> y=2x2-3x-1<br> y=x-3
4vir4ik [10]

Answer:

The value of x is 1 and y = -2

Step-by-step explanation:

y = 2x²- 3x - 1;

y = x - 3

2x²- 3x - 1 = x - 3

2x² - 3x - 1 - x + 3 = 0

2x² - 4x + 2 = 0

take 2 as common

2(x² - 2x + 1) = 0

x² - 2x + 1 = 0

x² - x - x + 1 = 0

x(x - 1) - 1(x - 1) = 0

(x - 1) (x - 1) = 0

x - 1 = 0 or x - 1 = 0

x = 1 or x = 1

Now,

y = x - 3

y = 1 - 3

y = - 2

Thus, The value of x is 1 and y is -2

<u>-TheUnknown</u><u>Scientist</u>

4 0
3 years ago
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