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3 years ago

10

A pound of fertilizer covers 47 square feet of lawn. Vivian Bulgakov lawn measures 8735.8 square feet. How much to the nearest t

enth of a pound does she need to buy

1 answer:

hoa [83]3 years ago

4 0

Answer:

185.9 pounds seems like the right answer.

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MULTIPLE CHOICE

Nina [5.8K]

Answer:

-2,-2 minimum

Step-by-step explanation:

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minimum because it is a minimum point it starts at the bottom

-2,-2 that is where the vertex is which is the point at the minimum

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caffeine takes a certain amount of time to leave your system if you drink 3 cups of coffee in the morning, the function that rep

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Of the 240 available seats for a concert, 63 seats were reserved. What fraction of seats was reserved? Write your answer in simp

Olin [163]

63/240 seats or 21/80
The greatest common denominator is 3, so you would divide both by 3.

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3 years ago

Find the sum. I need help.

Artyom0805 [142]

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B

Step-by-step explanation:

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You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

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1 year ago