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3 years ago

What is the probability of NOT choosing a 4?

Mathematics

1 answer:

Mariulka [41]3 years ago

7 0

9/16

7 of the squares are 4 so we just substract that from the total of 16 and we get 9

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Chris can be paid in one of two ways. Plan A is a salary of $490 per month, plus a commission of 9% of sales. Plan B is a sal

Tanya [424]

Step-by-step explanation:

Explanation:

First, when dealing with percents, "Percent" or "%" means "out of 100" or "per 100", Therefore x% can be written as

x/100.

The expression for Plan A can be written as:

490+(9/100)s where s is the sales for the month.

The expression for Plan B can be written as:

826+(3/100)s

The question we are being asked is when is Plan A > Plan B. So, we can write and solve this inequality:

490+(9/100)s>826+(3/100)s

490+(9/100)s−490−(3/100)s>826+(3/100)s−490−(3/100)s

490−490+(9/100)s−(3/100)s>826−490+(3/100)s−(3/100)s

0+(9/100)s−(3/100)s>826−490+0

(9/100)s−(3/100)s>826−490

(9/100−3/100)s>336

(6/100)s>336

(100/6)×(6/100)s>(100/6)×336

s> 33600/6

s>5,600

Plan A is better when sales for the month are greater than $5,600.

8 0

4 years ago

A. Part 1 ......Quadrilateral ABCD is similar to Quadrilateral EFGH. Diagonal AC has length 7 and diagonal EG has length 13. Wha

lianna [129]

Part three is the correct answer for the questions of an and

3 0

3 years ago

11 Prüfen Sie, ob die folgenden Aussagen wahr oder falsch sind. Begründen Sie.

tino4ka555 [31]

Answer: I don’t understand this language

Step-by-step explanation:

4 0

3 years ago

The diagram shows a circle inside a semicircle.

rjkz [21]

A circle inside a semicircle is depicted in the diagram. The circle measures 10 cm in diameter. The semicircle has a 20 cm diameter. Calculate the shaded area. Give a precise response to the nearest decimal point.

The area of the shaded region is 39.3 $cm^{2}$ .

Given the diagram shows a circle inside a semicircle.

Every point in the plane of a circle, which is a closed, two-dimensional object, is evenly separated from the center. All lines that cross the circle join together to produce the line of reflection symmetry. Every angle also possesses rotational symmetry about its center.

Area of a circle = $\pi r^{2}$ .

Semicircle is when a line travelling through the center of a circle reaches its two ends, a semicircle is created. Thus, a circle can be formed by combining two semicircles.

Area of a semicircle = $\frac{1}{2} \pi r^{2}$ .

The circle has a diameter of 10 cm. The semicircle has a diameter of 20 cm.

Semicircle:

$r_{1}=\frac{d_{1} }{2}=\frac{20}{2}=10cm\\S_{1}=\frac{ \pi r_{1}^{2} }{2} =\frac{ \pi \times 10^{2} }{2} =50\pi cm^{2}$

Circle:

$r_{2}=\frac{d_{2} }{2}=\frac{10}{2}=5cm\\S_{2}=\pi r_{2}^{2} = \pi \times 5^{2} =25\pi cm^{2}$

So,

$S=\frac{S_{1} -S_{2}}{2} \\S=\frac{50\pi -25\pi}{2}\\S=\frac{25\pi}{2} \\S=39.3cm^{2}$

Therefore, The area of the shaded region is 39.3 $cm^{2}$ .

To learn more about semicircle visit: brainly.com/question/3442660

#SPJ1

8 0

1 year ago

Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1.

Tresset [83]

As the directrix is parallel to x-axis, the concavity of the parabola will be in vertical. Then, the general equation is in the form: $(x-x_0)^2=2p(y-y_0)$ , where $(x_0,y_0)$ are the coordinates of the vertice and p is the parameter (distance between the focus and the directrix). The parameter is $p=1$ . The vertice is the midpoint between the focus and the projection of the focus in the directrix. Then, the vertice is $(6,2-\dfrac{1}{2})=(6,\dfrac{3}{2})$ . Hence, the parabola is: $(x-6)^2=2\cdot1\cdot(y-\dfrac{3}{2})\\\\x^2-12x+36=2y-3\\\\2y=x^2-12x+39\\\\\boxed{y=\frac{1}{2}x^2-6x+\dfrac{39}{2}}$ Now, derivating: $y'=\frac{1}{2}\cdot2x-6\\\\\boxed{y'=x-6}$

3 0

4 years ago

Read 2 more answers