B, D, E are appropriate choices.
_____
A ray can be named by its (one) end-point and any other point on the ray. Since there are an infinite number of points on the ray, it can be named an infinite number of ways.
Answer:
-150 (x^2y+2)y³
Step-by-step explanation:
To Find the product of 25x^2y and -6x²y3.
(25x^2y) (-6x²y³)
= 25(-6) (x^2y+2) y³
= -150 (x^2y+2)y³
Answer:
A = a + b / 2 x h
Step-by-step explanation:
Area is equal to side one plus side two divided by two then you multiply by the height of the trapezoid. Hope this helps!
Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B
