<u>Answer-</u>
<em>Maria's monthly payment will be </em><em>$376.91</em><em> </em>
<u>Solution-</u>
Maria is buying a car worth of $18,510, but she will finance only $13,000 of it with a 3-year loan at 2.8% APR.
We know that,
![\text{PV of annuity}=P[\dfrac{1-(1+r)^{-n}}{r}]](https://tex.z-dn.net/?f=%5Ctext%7BPV%20of%20annuity%7D%3DP%5B%5Cdfrac%7B1-%281%2Br%29%5E%7B-n%7D%7D%7Br%7D%5D)
Here,
![\text{PV of annuity=13000},\\\\\text{P=??},\\\\\text{r = 2.8\%\ annually}=\frac{2.8}{12}\text{\%\ monthly}\\\\\text{n=3 years=36 months}](https://tex.z-dn.net/?f=%5Ctext%7BPV%20of%20annuity%3D13000%7D%2C%5C%5C%5C%5C%5Ctext%7BP%3D%3F%3F%7D%2C%5C%5C%5C%5C%5Ctext%7Br%20%3D%202.8%5C%25%5C%20annually%7D%3D%5Cfrac%7B2.8%7D%7B12%7D%5Ctext%7B%5C%25%5C%20monthly%7D%5C%5C%5C%5C%5Ctext%7Bn%3D3%20years%3D36%20months%7D)
Putting the values,
![\Rightarrow 13000=P[\dfrac{1-(1+\frac{2.8}{1200})^{-36}}{\frac{2.8}{1200}}]](https://tex.z-dn.net/?f=%5CRightarrow%2013000%3DP%5B%5Cdfrac%7B1-%281%2B%5Cfrac%7B2.8%7D%7B1200%7D%29%5E%7B-36%7D%7D%7B%5Cfrac%7B2.8%7D%7B1200%7D%7D%5D)
![\Rightarrow 13000=P\times 34.4909](https://tex.z-dn.net/?f=%5CRightarrow%2013000%3DP%5Ctimes%2034.4909)
![\Rightarrow P=\dfrac{13000}{34.4909}](https://tex.z-dn.net/?f=%5CRightarrow%20P%3D%5Cdfrac%7B13000%7D%7B34.4909%7D)
![\Rightarrow P=376.91](https://tex.z-dn.net/?f=%5CRightarrow%20P%3D376.91)
Therefore, her monthly payment will be $376.91
The base formula for this equation can be represented as;
y=a√(x-h)+k <-- now substitute in the values
y=3√(x+1)+7
Just for your information;
a: vertical stretch/compression of the graph of √x, along with direction
h: translates the function to the left/right
k: translates the function upwards/downwards.
Answer:
![\frac{17}{42}](https://tex.z-dn.net/?f=%5Cfrac%7B17%7D%7B42%7D)
Step-by-step explanation:
The odds of the first sock being blue is:
or reduced to ![\frac{9}{14}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B14%7D)
The odds for the second sock being blue is:
![\frac{17}{27}](https://tex.z-dn.net/?f=%5Cfrac%7B17%7D%7B27%7D)
The odds of both happening is
![\frac{9}{14} X \frac{17}{27} = \frac{153}{378}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B14%7D%20X%20%5Cfrac%7B17%7D%7B27%7D%20%3D%20%5Cfrac%7B153%7D%7B378%7D)
This can be simplified by 9 resulting in ![\frac{17}{42}](https://tex.z-dn.net/?f=%5Cfrac%7B17%7D%7B42%7D)
Positive 3
hope this helps