The rate of the water flowing in the channel was 2 miles per hour, the rate Evelyn and Meredith were paddling is mathematically given as
v+ = 2.29 1mile/hour
<h3>What is the rate Evelyn and
Meredith were paddling?</h3>
Generally, the equation for the up and downstream motion is mathematically given as
vup=v-2
vdown=v+2
Therefore, Statement interpretation
2/3=40*1/60
3+2/3hr=11/3
Where, tup+tdown=11/3
tup+tdown=11/3
1/Vup+1/vdown=11/3
Considering the LCD equation
3(v-2)(V+2)
Hence

11v^2-6v-44=0

Resolving using the equation we have
v+ = 2.29 1mile/hour
v- = -1.745 mile hour
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QUESTION 1
The given system of equations are:


We equate the two equations to get:




When x=0,

The solution is (0,1)
QUESTION 2
The given equations are:

and

We equate both equations to get:

Group similar terms,



We put x=0 into any of the equations to find y.

The solution is (0,-1).
QUESTION 3
The given equations are:

and

We equate both equations:

Group similar terms:


This is not true.
Hence the system has no solution.
Answer:
12/16 = 3/4
I divided both sides by 4.
Hope this helps!
-Mikayla
Let y= years ago when dad's age was 4 times son's age
60-y=4(30-y)
60-y=120-4y
-y+4y=120-60
3y=60
y=60/3
y= 20 years ago
Then 30-20= 10 yrs. old, the boys age when his dad was 40 years old.