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vekshin1
3 years ago
12

How many ways are there for eight men and five women to stand in a line so that no two women stand next to each other? [hint: fi

rst position the men and then consider possible positions for the women.]?
Mathematics
1 answer:
EleoNora [17]3 years ago
6 0
Answer choices please ?
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What are the features of the parabola modeled by the equation f(x) = x2 - 114x ?
notsponge [240]

Answer:

Answers are in bold type

Step-by-step explanation:

f(x) = x^{2} -144x

The parabola opens up, so has a minimum at the vertex.

Let (h, k) be the vertex

h = -b/2a = - (-144)/2(1) = 57

k = 57^2 - 144(57) = 3249 - 6498 = -3249

Therefore, the vertex is (57, -3249)

The minimum value is -3249

The domain is the set of real numbers.  

The  range = {y | y ≥ -3249}

The function decreases when -∞ < x < 57  and increases when 57 > x > ∞

The x - intercepts:  x^{2} -144x = 0

                                x(x - 114x) = 0

                                x = 0 or x = 114

x-intercepts are (0, 0) and (0, 114)

When x = 0, then we get the y-intercept.  So, 0^2 - 114(0) = 0

y-intercept is (0, 0)

3 0
3 years ago
-5/7 x 1/5<br><br> please help
Molodets [167]

-5/7 x 1/5

-5 x 1 = -5

7 x 5 = 35

-5/35 = -1/7

Happy to help :P

3 0
2 years ago
(2 x 10^4) + (7 X 10^4) =
Lisa [10]
Quick what does ^ mean I can solve that but I need to know what ^ means.
5 0
3 years ago
Read 2 more answers
The circular mirror below has a frame with a circumference of 28.26 inches.
Karo-lina-s [1.5K]

Answer: it is 3

Step-by-step explanation:

6 0
3 years ago
Neeeeeed heeelp plz!!!
Blababa [14]
                             |
                             |__x_- 4___________              2x³/2x² =x
   2x² + 2x +3        | 2x³ - 6x² +7x +3
                            - (<span>2x³ +2x² +3x)
</span>                                      -8x² +4x  +3                -8x²/2x² = -4
                                    <span>-(-8x² -8x  -12)
</span>                                              12x +15

(x-4) + (12x +15)/(2x² + 2x +3) 
6 0
3 years ago
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