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3 years ago

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How many ways are there for eight men and five women to stand in a line so that no two women stand next to each other? [hint: fi

rst position the men and then consider possible positions for the women.]?

1 answer:

EleoNora [17]3 years ago

6 0

Answer choices please ?

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sergejj [24]

Answer:

6) y = -x - 5

7) y = $\frac{7}{5}$ x + 3

Step-by-step explanation:

format y = mx + b

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2 years ago

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AlexFokin [52]

Answer:

3/8

Step-by-step explanation:

Rearrange, find common denominator.

$x = \frac{7}{8} - \frac{1}{2} \\ x = \frac{7}{8} - \frac{4}{8} \\ x = \frac{3}{8}$

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2 years ago

the width of Jana's rectangular classroom is 1 meter more then 1/4 of its length. if the perimeter of the classroom is 24 meters

Bumek [7]

Let's call the length L, the width w.
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L+w=L+(1+L/4)=5L/4+1=12
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2 years ago

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Can someone help me please?

Sedaia [141]

Answer:

A

Step-by-step explanation:

12*3 = 36 = A

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