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vekshin1
3 years ago
12

How many ways are there for eight men and five women to stand in a line so that no two women stand next to each other? [hint: fi

rst position the men and then consider possible positions for the women.]?
Mathematics
1 answer:
EleoNora [17]3 years ago
6 0
Answer choices please ?
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50 points decreased by 26%
RoseWind [281]
Get the decimal version of 26% by moving the decimal (at the end) over to spots, giving you .26. Multiply 50 by this, and you get .26*50=13. : )
6 0
2 years ago
Read 2 more answers
– 36 – m = 8(4 + 2m)
valentina_108 [34]

Answer:

m = -4

Step-by-step explanation:

- 36 - m = 8(4+2m)

- 36 - m = 32+16m (to remove m from the left side, we need to add m to both sides)

- 36 = 32+17m (subtract 32 from both sides)

- 68 = 17m (divide by 17 on both sides)

-4 = m

5 0
2 years ago
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Solve for r in terms of s, t, and u. <br> t=u-s+r
Verdich [7]

Answer:

r = t - u - s

Step-by-step explanation:

To solve for r in terms of s, t, and u, means to have r on one side and have t, u, and s.

t = u - s + r

t - u = s + r

t - u - s = r

6 0
2 years ago
If muffins cost 5.24 how much would 5 muffins cost
natta225 [31]
5.24 x 5 = $26.2
5 Muffins would cost $26.2
3 0
2 years ago
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Help please!<br><br> | 2x^2 + 5x + 3 | &gt; 0<br> solve the inequality
vovikov84 [41]

Factorize the quadratic.

2x^2 + 5x + 3 = (2x + 3) (x + 1)

We have |ab| = |a||b|, so

|2x^2 + 5x + 3| = |2x + 3| |x + 1| > 0

Now, both |2x+3|\ge0 and |x+1|\ge0 (since the absolute value of any number cannot be negative), so we just need to worry about when the left side is exactly zero. This happens for

(2x + 3) (x + 1) = 0 \implies 2x+3 = 0\text{ or }x+1 = 0 \\\\ \implies x = -\dfrac32 \text{ or } x = -1

So the solution to the inequality is the set

\left\{x \in \Bbb R \mid x\neq-\dfrac32 \text{ and } x\neq-1\right\}

3 0
2 years ago
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