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3 years ago

3 feet, 9 inches plus 6 feet, 1 inch is equal to 3 yards, 10 inches .. true or false?

Mathematics

2 answers:

Brilliant_brown [7]3 years ago

8 0

Answer:

true

Step-by-step explanation:

s2008m [1.1K]3 years ago

7 0

This is true. 3 feet is 1 yard, 6 feet is 2 yards so that’s 3 yards and 9 inches and 1 inch is 1 inches so that would be 3 yards and 10 inches.

Hope this helps you

-AaronWiseIsBae

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Invest $6,300 in two different accounts the first account paid 11% the second account paid 6% in interest at the end of the year

MAVERICK [17]

Answer: he invested $5300 at 11% and $1000 at 6%

Step-by-step explanation:

Let x represent the amount which he invested in the first account paying 11% interest.

Let y represent the amount which he invested in the second account paying 6% interest.

He Invest $6,300 in two different accounts the first account paid 11% the second account paid 6% in interest. This means that

x + y = 6300

The formula for determining simple interest is expressed as

I = PRT/100

Considering the first account paying 11% interest,

P = $x

T = 1 year

R = 11℅

I = (x × 11 × 1)/100 = 0.11x

Considering the second account paying 6% interest,

P = $y

T = 1 year

R = 6℅

I = (y × 6 × 1)/100 = 0.06y

At the end of the year, he had earned $643 in interest , it means that

0.11x + 0.06y = 643 - - - - - - - - - -1

Substituting x = 6300 - y into equation 1, it becomes

0.11(6300 - y) + 0.06y = 643

693 - 0.11y + 0.06y = 643

- 0.11y + 0.06y = 643 - 693

- 0.05y = - 50

y = - 50/ - 0.05

y = 1000

x = 6300 - y = 6300 - 1000

x = 5300

7 0

3 years ago

Of all customers purchasing automatic garage-door openers, 70% purchase a chain-driven model. Let X = the number among the next

otez555 [7]

Answer:

P(X > 10), n = 15, p = 0.7

P(X > 10) =P(10 < X ≤ 15) = P(11 ≤ X ≤ 15) = P(X = 11, 12, 13, 14, 15)

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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malfutka [58]

Answer:

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3 years ago

What is a common factor for the two fractional terms StartFraction 5 over 8 EndFraction x andStartFraction 11 over 8 EndFraction

Dafna1 [17]

Answer:

$\frac{1}{8x}$

Step-by-step explanation:

Given two fractional terms $\frac{5}{8x}\ and\ \frac{11}{8xy}$ . Their common factor is a value or function that can go in both fractional terms. The terms can be written as shown.

$\frac{5}{8x} = 5 *\frac{1}{8x}$

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It can be seen from the both equations that they both have $\frac{1}{8x}$ as one of their factors i.e <em>1/8x is common to both fractional terms</em>. This gives the common factor for the two fractional terms as $\frac{1}{8x}$

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3 years ago

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