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miv72 [106K]
2 years ago
15

Plz help me!! Will give brainliest to who ever gets it right! Thanks

Mathematics
2 answers:
GarryVolchara [31]2 years ago
6 0

Answer:

5. 57  9. 63

Step-by-step explanation:

Im Smart

likoan [24]2 years ago
5 0

Answer:

4 and 5 the answer choices are wrong. 6.=150 9.=63. 10.=vertical. i dont have the chart for 8

Step-by-step explanation:

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What's the answer to this problem
Anna71 [15]
Um I think if you multiply the amount of hersheys by the ribbon you would get youre answer
Hoped i helped i couldn't see the number of ribbons
5 0
2 years ago
What is 3/4 ÷ 1/6? Please help !......
Reika [66]

Answer:

4 1/2

Step-by-step explanation:

Apply the fractions formula for division, to

3/4÷1/6

and solve

3/6x4/1

=18/4

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(18,4) = 2

18/24÷2/2=9/2

Convert to a mixed number using

long division for 9 ÷ 2 = 4R1, so

9/2=4 1/2

Therefore:

3/4÷1/6=4 1/2

4 0
2 years ago
A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a stand
Art [367]

Answer:

b. Mean = 1.6 years, standard deviation - 0.92 years, shape: approximately Normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal Variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a standard deviation of 4.2 years. Sample of 35:

This means that:

\mu_G = 15

s_G = \frac{4.2}{\sqrt{35}} = 0.71

The distribution of life spans for electric ranges has a mean of 13.4 years and a standard deviation of 3.7 years. Sample of 40:

This means that:

\mu_E = 13.4

s_E = \frac{3.7}{\sqrt{40}} = 0.585

Which of the following best describes the sampling distribution of the difference in mean life span of gas ranges and electric ranges?

Shape is approximately normal.

Mean:

\mu = \mu_G - \mu_E = 15 - 13.4 = 1.6

Standard deviation:

s = \sqrt{s_G^2+s_E^2} = \sqrt{0.71^2+0.585^2} = 0.92

So the correct answer is given by option b.

8 0
3 years ago
A __________ is a graphical summary of data previously summarized in a frequency distribution. a. box plot b. histogram c. scatt
OLga [1]

Answer: b. histogram

Step-by-step explanation:

A histogram is a graphical summary of data previously summarized in a frequency distribution. It is an accurate representation of the distribution of numerical data, the height of each bar shows how many fall into each range(the frequency of each range). Data from a frequency distribution table can be easily summarised graphically on a histogram.

An example of histogram is shown in the attachment

8 0
3 years ago
Write two other forms 80+7+0.9+0.03
yarga [219]
87.93
eighty seven and ninety-three hundreths
7 0
2 years ago
Read 2 more answers
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