<span>1/5(2x-15) + (3/5)x = 4 1/4
</span><span>x*2/5 - 15/5 + x*3/5 = 4 1/4
</span><span>x*2/5 - 3 + x*3/5 = 4 1/4
</span><span>x*(2/5+3/5) - 3 = 4 1/4
</span><span>x*(5/5) - 3 = 4 1/4
</span>1*x - 3 = 4 1/4
<span>x= 4 1/4 + 3
</span><span>x= 7 1/4 </span>
Answer:
Step-by-step explanation:
Given :-
The sum of two numbers is 1 .
The product of the nos . is 12 .
And we need to find out the numbers. So let us take ,
First number be x
Second number be 1-x .
According to first condition :-
Hence the numbers are 4 and -3.
C.264.4 that should answer your question
To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square.
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial.
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2.
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial.
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1.
They are both 1.
x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
or (x+1)^2.
I think (-6,-2) because it would switch into the all negative quadrant making them both negative.
