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Alona [7]
3 years ago
13

What is an equation with more than one variable called

Mathematics
2 answers:
atroni [7]3 years ago
8 0
A) literal equation
strojnjashka [21]3 years ago
3 0

Answer:

option A

a variable is a number which is always changing

an  expression doesn't have an equal sign

a quadratic equation is an equation which has one variable but the highest power of that variable is 2

so the answer is a literal equation or linear equation in two variables

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Choose the correct symbol to complete the statement.<br><br> 4.105 _____ 4.15
kogti [31]
< is the answer. Hope this helps!
4 0
3 years ago
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Please help me I need to get this done
OverLord2011 [107]
The square root of 64 is 8 and the square root of 100 is 10.... so,

square root of 64/100 = 8/10

8/10 reduces to 4/5

Answer D.
4 0
3 years ago
16x2 + 81y2 + 32x + 648y + 16 = 0 write instandard form
satela [25.4K]
I can’t answer it doesn’t have enough information
7 0
2 years ago
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Arada [10]

Using a confidence interval of proportions, it is found that the correct statement is given by:

D a confidence interval for estimating the cricket's true probability of landing on its feet is more narrow after the final 10 jumps than it was before the final 10 jumps.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is inversely proportional to the square root of the sample size, hence, the higher the sample size, the narrower the interval is, hence option D is correct.

More can be learned about a confidence interval of proportions at brainly.com/question/25890103

7 0
2 years ago
Alice, Benjamin, and Carol each try independently to win a carnival game. If their individual probabilities for success are 1/5,
kicyunya [14]

Answer:

E. 7/40

Step-by-step explanation:

The following probabilities are given:

P (Alice Wins) = 1/5

P (Benj. Wins) = 3/8

P (Carol Wins) = 2/7

We can deduce the probabilities for losses:

P (Alice Loses) = 1 - P (Alice Wins) = 1 - 1/5 =4/5

P (Benj. Loses) = 1 - P (Benj. Wins) = 1 - 3/8 = 5/8

P (Carol Loses) = 1 - P (Carol Wins) = 1 - 2/7 =5/7

The possible outcomes that two players win and one player loses are as follows:

Alice Wins, Benj Wins, Carol Loses

Alice Loses, Benj Wins, Carol Wins

Alice Wins, Benj Loses, Carol Wins

We can compute the probabilities of each of the 3 outcomes above:

P(Alice Wins, Benj Wins, Carol Loses) = (1/5) x (3/8) x (5/7) = 3/56

Alice Loses, Benj Wins, Carol Wins = (4/5) x (3/8) x (2/7) = 3/35

Alice Wins, Benj Loses, Carol Wins = (1/5) x (5/8) x (2/7) =  2/56

P ( 2 wins and 1 loss)

= 3/56 + 3/35 + 2/56

= 343 / 1960

= 7/40

7 0
3 years ago
Read 2 more answers
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