Answer:
i)16
ii)9
Step-by-step explanation:
![\sqrt{256} \\=\sqrt{16*16} \\=16\\\\ii)\ \sqrt[3]{729}\\ =\sqrt[3]{9*9*9} \\=9](https://tex.z-dn.net/?f=%5Csqrt%7B256%7D%20%5C%5C%3D%5Csqrt%7B16%2A16%7D%20%5C%5C%3D16%5C%5C%5C%5Cii%29%5C%20%5Csqrt%5B3%5D%7B729%7D%5C%5C%20%3D%5Csqrt%5B3%5D%7B9%2A9%2A9%7D%20%5C%5C%3D9)
Answer & Explanation:
To find the direction cosines of the vector a is need to divided the corresponding coordinate of vector by the length of the vector. The coordinates of the unit vector is equal to its direction cosines. Property of direction cosines. The sum of the squares of the direction cosines is equal to one.
Answer:
76 degrees
Step-by-step explanation:
The total of the three angles in a triangle should equal 180 degrees. So to find the third angle, subtract the two given angles from 180
180 - 87 = 93
93 - 17 = 76
The third angle is 76 degrees because then all angles will add up to 180
Look at the last digit. If the last digit is 0, then the number can be divided by 10 <span> evenly (without a remainder).</span>
Angle BAC
cosφ⁻¹ = (10² + 17² - 11²)/(2*10*17) = 37.9 ≈ 38°
Angle ACB
cosφ⁻¹ = (10² + 11² - 17²)/(2*10*11) = 108.0°
Angle ABC
cosφ⁻¹ = (11² + 17² - 10²)/(2*11*17) = 34.0°
See you !
