Question

Help please thnk you!!!!

Answer 1

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✲ TanakaBro is here to help! ✲  

$The$ $answer$ $to$ $this$ $is$ $B$:

⋆ FIRST:

 

$4x=y$

$2x^2 -y =0$ So then we need to Substitute of the y value from the first equation, inside. And the second equation, in the place we get y at.

$2x^2 -4x =0$ then we have to solve for the y.

 ⋆ EXPLANATION OF THE ANSWER HOW WE SOLVE:

$2x^2 -4x =0\\2x(x-2) =0x_1 = 0x - 2 =0x_2 = 2 2x =0$

So for the $x$_ $1 = 4*0 = 0$ So the solution is $(0,0)$ And that case of

Hopefully that helped you!

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- $Answer$

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