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kiruha [24]
1 year ago
13

Sam is installing a walkway around a rectangular flower patch in his garden. The flower patch is 12 feet long and 6 feet wide. T

he width of the walkway is x feet. Sam created function A to represent the total area taken up by the flower patch and walkway by multiplying the functions modeling the new total length and width. What does represent in this function
Mathematics
1 answer:
rodikova [14]1 year ago
4 0

In the function, the thing that is represented is the area of the walkway along the length of the flower patch.

<h3>How to illustrate the function?</h3>

From the information given, Sam created function A to represent the total area taken up by the flower patch and walkway by multiplying the functions modeling the new total length and width.

Therefore, the thing that is represented is the area of the walkway along the length of the flower patch.

Learn more about functions on:

brainly.com/question/25638609

#SPJ1

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A leprechaun places a magic penny under a girls pillow. The next night there are 2 magic pennies under her pillow. The following
kiruha [24]

Answer:

<em>After </em><em>47</em><em> days she will have more than 90 trillion pennies.</em>

Step-by-step explanation:

At the beginning there was 1 penny. At the second day the amount of pennies under the pillow became 2.

The amount of pennies doubled each day. So the series is,

1,2,4,8,16,32,.....

This series is in geometric progression.

As the pennies from each of the previous days are not being stored away until more pennies magically appear so the sum of series will be,

S_n=\dfrac{a(r^n-1)}{r-1}

where,

a = initial term = 1,

r = common ratio = 2,

As we have find the number of days that would elapse before she has a total of more than 90 trillion, so

\Rightarrow 90\times 10^{12}\le \dfrac{1(2^n-1)}{2-1}

\Rightarrow 90\times 10^{12}\le \dfrac{2^n-1}{1}

\Rightarrow 90\times 10^{12}\le 2^n-1

\Rightarrow 2^n\ge 90\times 10^{12}+1

\Rightarrow \log 2^n\ge \log (90\times 10^{12}+1)

\Rightarrow n\times \log 2\ge \log (90\times 10^{12}+1)

\Rightarrow n \ge \dfrac{\log (90\times 10^{12}+1)}{\log 2}

\Rightarrow n \ge 46.4

\Rightarrow n\approx 47


8 0
3 years ago
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