the answer to this is 2 and 3
Hope this helped
-scav
Answer:
The solution code is written in Python 3
- digits = input("Enter 9 digits: ")
-
- multiplier = 1
- total = 0
-
- for x in digits:
- total += int(x) * multiplier
- multiplier += 1
-
- checksum = total % 11
-
- if(checksum == 10):
- print(digits + "X")
- else:
- print(digits + str(checksum))
Explanation:
Firstly, use input function to get user input for 9 digits (Line 1)
Next we can use a for-loop to estimate the summation (d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5+ d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9) ( Line 6-8)
Then only apply % operator to get the remainder of total and get the checksum (Line 10)
Next create if and else statement to print the digits string joined with X if checksum is 10 else join digits string with checksum value (Line 12 -15)
Answer:
Both compiled and interpreted languages are high-level languages and translate code for a computer to understand.
Explanation:
The one similarity between compiled and interpreted languages is that they are both high-level languages.
A high-level language is a computer language written in easy to understand human language which is then converted to machine code for the computer to understand.
A high-level language can either be interpreted or compiled.
An interpreted is a language in which the code is translated line by line before execution while a compiled language is one in which the source code is converted directly into machine language before execution.
So, <u>the similarity between both languages is that they are high level languages and translate code for a computer to understand. </u>
Answer:
d) daco = new Banana;
Explanation:
Dynamically allocated variables have their memory allocated in the heap memory.We declare a dynamical variable like this:-
int *a=new int ;
It means a pointer a is created on the stack memory which hold the address of the block that hold the value of variable a in heap memory.
We already have the pointer daco. We just have to initialize with keyword new.
It will be like daco=new Banana; which matches the option d.
