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2 years ago

1 2/3 + (2 1/2) = ? pls help

Mathematics

2 answers:

DIA [1.3K]2 years ago

8 0

1 2/3+(2 1/2)
3+2/3+1/2
3+2x2/3x2+1x3/2x3
3+4/6+3/6
3+4+3/6
3+7/6
3+1 1/6
4 1/6

Answer: 4 1/6

Sever21 [200]2 years ago

3 0

The answer is about 4.1.

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Factorize:<br> 2ax-6ay+bx-3by

Elodia [21]

Answer:

2ax − 6ay + bx − 3

Step-by-step explanation:

The expression is not factorable with rational numbers

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3 years ago

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A city park commission received a donation of playground equipment from a parents' organization. The area of the playground need

dalvyx [7]

Answer:

Length = 20.49 yards and Width = 12.49 yards.

Step-by-step explanation:

The area of the rectangular playground is given by 256 yards square. It is also known that one of the sides of the playground is 8 yards longer than the other side. Therefore, let the smaller side by x yards. Then the longer side will be (x+8) yards. The area of the rectangle is given by:

Area of the rectangle = length * width.

256 = x*(x+8)

x^2 + 8x = 256. Applying the completing the square method gives:

(x)^2 + 2(x)(4) + (4)^2 = 256 + 16

(x+4)^2 = 272. Taking square root on both sides gives:

x+4 = 16.49 or x+4 = -16.49 (to the nearest 2 decimal places).

x = 12.49 or x = -20.49.

Since length cannot be negative, therefore x = 12.49 yards.

Since smaller side = x yards, thus smaller side = 12.49 yards.

Since larger side = (x+8) yards, thus larger side = 12.49+8 = 20.49 yards.

Thus, the length and the width to minimize the perimeter of fencing is 20.49 yards and 12.49 yards respectively!!!

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4 years ago

Chris's uncle has a model car. The model is 6 inches long and 3 inches wide. The actual car is 75 inches long. What is the actua

krek1111 [17]

6/75=3/x
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3 years ago

A town’s January high temperatures average 36 degrees (F) with a standard deviation of 10 degrees while in July the mean high

n200080 [17]

Answer:

55 degrees is more unusual in July as it is away from mean temperature as compared to January.

Step-by-step explanation:

We are given the following information in the question:

January:

Mean, μ = 36 degrees

Standard Deviation, σ = 10 degrees

July:

Mean, μ = 74 degrees

Standard Deviation, σ = 8 degrees

We calculate z scores corresponding to x = 55.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

January:

$z_{score} = \displaystyle\frac{55-36}{10} = 1.9$

July:

$z_{score} = \displaystyle\frac{55-74}{8} = -2.375$

Thus, 55 degrees is more unusual in July as it is away from mean temperature as compared to January.

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3 years ago

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<span>$2,022.92 would be the answer

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3 years ago

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