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Eduardwww [97]
3 years ago
9

What is the constant term this equation

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

there is no constant term. it contains a variable x. in this 1 is coefficient of x.

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Tasha says that the expression 6.8w-4.7 can be simplified as 2.1w. Her teacher explains that this is not correct. What mistake d
tatuchka [14]

Answer: She combined unlike terms.

Step-by-step explanation:

You can only combine like terms. If a number has a variable, you must make sure that the number you're operating it with has the same variable raised to the same power (if applicable)

6.8w-4.7 is in its simplest form.

To be able to subtract these, 4.7 must have a ''w'' variable as follows;

6.8w-4.7w=2.1w

7 0
3 years ago
Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
2 years ago
Write the solution of the given system of equations
Citrus2011 [14]

Answer:

Step-by-step explanation:

The solution to this system of equation is (4, 10)

3 0
3 years ago
Show all work to factor x4 − 10x2 + 9 completely.
leva [86]

Answer:

(x+1)(x-1)(x+3)(x-3)

Step-by-step explanation:

x4-10x^2+9

Group expression so that the coefficients of the x^2 terms add up to +9.

= x^4 -9x^2   - x^2+9

match coefficients in both groups

= x^4 -9x^2   - (x^2-9)

factor each group

= x^2 (x^2-9) - 1(x^2-9)

now factor out the common factor (x^2-9)

= (x^2-1)(x^2-9)

Finally, factor each quadratic factor

= (x+1)(x-1)(x+3)(x-3)

6 0
3 years ago
Read 2 more answers
Currently, in Littlefield, jobs arrive at 12 per day and you have (just) enough capacity at each station (i.e., the departure ra
OlgaM077 [116]

Answer:

The WIP limit is 0.50 days.

Step-by-step explanation:

The Computation of WIP limits:

to begin with, it is required to compute the process and procedure efficiency which will be computed as follows:

Value Added Time = 12 days (arriving time)

Non-Value-Added Time = 12 days (departure time)

Efficiency = Value Added / (Value Added + Non-Value Added)

                = 12 / (12+12)

                = 12 / 24

               = 0.50 or 50%

the most obligatory throughput time will be 0.25 days to realize the profits

WIP limit = Throughput time / Efficiency  

               = 0.25 / 50%

               = 0.50 days.

The WIP limit is 0.50 days.

6 0
3 years ago
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