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Kryger [21]
2 years ago
12

An auto travels at a rate of 25 km/hr for 4 minutes, then at 50 km/hr for 8 minutes, and finally at 20 km/hr for 2 minutes. find

the total distance covered in km and the average speed for the complete trip in m/s.
Mathematics
1 answer:
ankoles [38]2 years ago
3 0

We know that the formula for calculating distance is:

distance d = velocity v * time t

 

Calculating for each interval:

 

1: 25 km/hr for 4 minutes

d1 = (25 km / 60 min) (4 min) = 1.67 km

 

2: 50 km/hr for 8 minutes

d2 = (50 km / 60 min) (8 min) = 6.67 km

 

3: 20 km/hr for 2 minutes

d2 = (20 km / 60 min) (2 min) = 0.67 km

 

The total distance covered is:

d = d1 + d2 + d3

d = 1.67 + 6.67 + 0.67

d = 9 km

 

The average speed is:

s = 9 km (1000 m / km) / (14 min * 60 s / min)

s = 10.72 m / s

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Andreas93 [3]

Answer:

(f - g)(x) = 3x² - 2x - 6

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 3x² - 2

g(x) = 2x + 4

(f - g)(x) is f(x) - g(x)

<u>Step 2: Evaluate</u>

  1. Substitute:                    (f - g)(x) = 3x² - 2 - (2x + 4)
  2. Distribute -1:                 (f - g)(x) = 3x² - 2 - 2x - 4
  3. Combine like terms:    (f - g)(x) = 3x² - 2x - 6
5 0
3 years ago
Solve the equation 29 - (x+8) = 6x - 7
max2010maxim [7]
First step you should do is s<span>implify both sides of your equation:
</span>29-(x+8)=6x-7
Distribute the Negative Sign:
29+-1(x+8)=6x-7
29+-1x+(-1)(8)=6x-7
29+-x+-8=6x-7
29+-x+-8=6x+-7
<span>Combine Like Terms:
</span>(-x)+(29+-8)=6x-7
-x+21=6x-7
<span>Subtract 6x from both sides:
</span>-x+21-6x=6x-7-6x
-7x+21=-7
<span>Subtract 21 from both sides:
</span>-7x+21-21=-7-21 
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</span>-7x/-7 = -28/-7
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x=4
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Good luck~ Sans
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2 years ago
The collection of all value is called the range of the function​
Phoenix [80]

Answer:

Step-by-step explanation:

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3 years ago
Solve 152x = 36. Round to the nearest ten-thousandth. 1.7509 2.6466 0.6616 1.9091
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6 0
3 years ago
Read 2 more answers
A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran
Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0
3 years ago
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