Please help me ASAP!!

Last year, Keiko had $20,000 to invest. She invested some of it in an account that paid %7 simple interest per year, and she inv

erma4kov [3.2K]

Answer:

$P_2 = \$6,000\\P_1 = \$14,000$

Step-by-step explanation:

The formula of simple interest is:

$I = P_0rt$

Where I is the interest earned after t years

r is the interest rate

$P_0$ is the initial amount

We know that the investment was $20,000 in two accounts

_______________________________________________

For the first account r = 0.07 per year.

Then the formula is:

$I_1 = P_1r_1t$

Where

$P_1$ is the initial amount in account 1 at a rate $r_1$ during t = 1 year

$I_1 = P_1(0.07)(1)\\\\I_1 = 0.07P_1$

For the second account r = 0.05 per year.

Then the formula is:

$I_2 = P_2r_2t$

Where

$P_2$ is the initial amount in account 2 at a rate $r_2$ during t = 1 year

Then

$I_2 = P_2(0.05)(1)\\\\I_2 = 0.05P_2$

We know that the final profit was I $1,280.

So

$I = I_1 + I_2=1,280$

Substituting the values $I_1$ , $I_2$ and I we have:

$1,280 = 0.07P_1 + 0.05P_2$

As the total amount that was invested was $20,000 then

$P_0 = P_1 + P_2 = 20,000$

Then we multiply the second equation by -0.07 and add it to the first equation:

$0.07P_1 + 0.05P_2 = 1.280\\.\ \ \ \ \ \ \ \ +\\-0.07P_1 -0.07P_2 = -1400\\-------------$

$-0.02P_2 = -120\\\\P_2 = 6,000$

Then $P_1 = 14,000$

4 0

3 years ago

What is the value of y−5x−3for x = 2 and y = -4

arlik [135]

Answer

-17

Explanation

y−5x−3 for x = 2 and y = -4

We solve this question by substituting the values of y and x.

y−5x−3 = -4 - 5(2) - 3

= -4 - 10 -3

= -14 - 3

= -17

8 0

4 years ago

Read 2 more answers

Find all solutions in the interval [0, 2π). 4 sin2x - 4 sin x + 1 = 0

Eddi Din [679]

Answer:

x = π/6, 5π/6

Step-by-step explanation:

4 sin² x − 4 sin x + 1 = 0

(2 sin x − 1)² = 0

sin x = ½

x = π/6, 5π/6

5 0

3 years ago

HELP!!! IM DOING A TIMED ASSIGNMENT!!

inna [77]

Answer:

7/50 (also 18% if u need it)

Step-by-step explanation:

18/100 ----- 7/50

Hope this helps!

6 0

3 years ago

Read 2 more answers

Graph the function -2x+5y=10

loris [4]

An equation of the form ax+by+c=0, where x, y are variable, and a, b, c are numbers, is called a "linear equation"

the reason we call it linear, is that all solutions (x, y) to this equation, when plotted in the x-y axis, form a line.

To draw this line, 2 points are enough, that is 2 solutions (x, y) of the equation.

-------------------------------------------------------------------------------------------------

-2x+5y-10=0 is a linear equation (a=-2, b=5, c=-10)

to find 2 solutions, we set x or y any value we want, and solve for the other

for example:

let x=0,

then

-2x+5y-10=0 becomes 5y-10=0, so y=2

this gives us the solution (0, 2)

another example; set y=0

then -2x+5y-10=0 becomes -2x-10=0; -2x=10 so x=-5

thus another solution is (-5, 0)

Draw these 2 points, and join them with a line, as shown in the figure.

6 0

3 years ago