Please help me ASAP!!

Alan's go kart travels 1750 feet per minute and Barry's go kart travels 21 miles per hour whose go kart travels faster round you

krok68 [10]

Answer:

Barry's kart is faster as he goes 21 Mph while Alan only goes 19.89 Mph.

Step-by-step explanation:

First to get this answer we need to convert feet per minute to miles per hour. So we multiple 1750 feet per minute by 60 to get a hour. This gets up 105000 total feet in a hour. Now we need to divide this by 5280, which is how long a mile is, to get 19.89 miles which is how many miles he travels in a hour making him travel 19.89 mph which is less than 21 making Barry faster.

7 0

3 years ago

What is 0.6 as a fraction is simplest form

Darina [25.2K]

0.6 is 6 tenths. 6/10 is the fraction form but you have to simplify so it becomes 3/5.

4 0

3 years ago

A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr

ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so $\pi = 0.30$

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so $n = 10$

We want to find P(X = 1). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211$

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is $P(X > 1)$

We have that:

$P(X \leq 1) + P(X > 1) = 1$

$P(X > 1) = 1 - P(X \leq 1)$

We also have that:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282$

So

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493$

Finally

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507$

There is a 85.07% probability that more than 1 has the marker.

3 0

3 years ago

What is the sum of 1/3 and 2/9?

Sergio039 [100]

Answer:

5/9

Step-by-step explanation:

1/3=3/9

3/9+2/9=5/9

7 0

3 years ago

What is the x-intercept of the group of the function f(x) =x2 -16x + 64

Dimas [21]

The x-intercept of a function is basically it's roots. So when you factor out the function f(x) = x^2 - 16x + 64 you get

(x-8)(x-8)

x = 8

So x-int. is (0,8) or x = 8

3 0

3 years ago