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ikadub [295]
3 years ago
13

For the following problem, which operation should be done first? 42 ÷ (12 ÷ 2) 42 ÷ 2 12 ÷ 2 42 ÷ 6 42 ÷ 12

Mathematics
2 answers:
slamgirl [31]3 years ago
6 0
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ 12 / 2 would need to be done as this follows the rules of PEMDAS

P (parenthesis)

E (exponents)

M (multiplication)

D (division)

A (addition)

S (subtraction)

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

solmaris [256]3 years ago
5 0
Divided 12 by 2 first because it is in the parentheses
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If you multiply the four-digit number abcd by 4, the order of digits will be reversed. That is, abcd x 4=dcba. The digits a, b,
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The given is that A B C D <span>x 4 = D C B A
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Possible values of A are 1 or 2. It can't be 1 since the </span><span> </span><span>final result A is in unit place and 1 is not possible when we multiply any number by 4
</span><span>
2 B C D x </span><span>4 = </span><span>D C B 2</span>
It is clear above, that D = 8
2 B C 8 x <span>4 = </span><span>8 C B 2</span>
Possible values of B should be 1 or 2
We try B=1

2 1 C 8 x <span>4 = </span><span>8 C 1 2

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C = 7
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4 years ago
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Can someone help me find the answer to these 3 problems if so thank you .
alexandr1967 [171]

Answer:

1. r+s²=49

2. pq²=24

3. -4xy-6x²+2x²y-6y= -54

Step-by-step explanation:

1. r+s²=0+7²=49

2. pq²=(6)(2)²=6(4)=24

3. -4xy-6x²+2x²y-6y= -4(3)(2)-6(3)²+2(3)²(2)-6(2)

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                                = -24-54+36-12

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                                = -54

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3 years ago
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