Question

Whats the answer for y=-{2}{3}" align="absmiddle" class="latex-formula">x+4 and y=$\frac{1}{3}$x-2

Answer 1

Step-by-step explanation:

$y = -\frac{2}{3}x + 4$

$y = \frac{1}{3}x - 2$

Since both equations are set equal to $y$, we can take the right-hand side of each equation and set them equal to each other to solve for $x$:

$-\frac{2}{3}x + 4 = \frac{1}{3}x - 2$

$-\frac{2}{3}x - \frac{1}{3}x = -2 - 4$

$-x = -6$

$x = 6$

Now we can plug this value into either equation to solve for $y$:

$y = \frac{1}{3}x - 2$

$y = \frac{1}{3}(6) - 2$

$y = 2 - 2$

$y = 0$

So the solution to the system of equations is $(6, 0)$