Answer:
Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
![\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D)
i)
To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.
We have to make it in steps like follows.
Cube both sides:
![\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E3%3D%5Cleft%28%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D%5Cright%29%5E3)
Simplify the radical with the cube:
Multiply by 2y+9
Simplify:
Operate the parentheses:
Subtract 3y and 
:
Factor y out of the left side:
Divide by 
:
ii) To find y when x=2, substitute:
Answer:
X+5
Step-by-step explanation:
Hell there!
You just need to express X raised by five in algebraic notation.
:)
(0, 2 ), (4,5)
to draw a graph of a straight line , we only require 2 points
select any 2 values for x, substitute them into the equation for the corresponding y- coordinates
x = 0 → y = 0+2 = 2 ⇒ (0, 2)
x = 4 → y = 3+2 = 5 ⇒ (4, 5)
Plot these 2 points and draw a straight line through them for graph
Answer:
90:180, 135:270, 180:360
Step-by-step explanation:
Answer:
xvideos
Step-by-step explanation:
