Answer:
![[f(x)]^2-g(x) = 5x^2-13x-8](https://tex.z-dn.net/?f=%5Bf%28x%29%5D%5E2-g%28x%29%20%3D%205x%5E2-13x-8)
Step-by-step explanation:
Given
To find: ![[f(x)]^2-g(x)](https://tex.z-dn.net/?f=%5Bf%28x%29%5D%5E2-g%28x%29)
First of all the square of first function f(x) will be found and then second function g(x) will be subtracted from the square of first function
Squaring the first function
![[f(x)]^2 = (2x-2)^2\\Using\ (a-b)^2 = a^2-2ab+b^2\\\[f(x)]^2 = (2x)^2-2(2x)(2)+(2)^2\\= 4x^2-8x+4](https://tex.z-dn.net/?f=%5Bf%28x%29%5D%5E2%20%3D%20%282x-2%29%5E2%5C%5CUsing%5C%20%28a-b%29%5E2%20%3D%20a%5E2-2ab%2Bb%5E2%5C%5C%5C%5Bf%28x%29%5D%5E2%20%3D%20%282x%29%5E2-2%282x%29%282%29%2B%282%29%5E2%5C%5C%3D%204x%5E2-8x%2B4)
Now subtracting g(x) from [f(x)]^2
![[f(x)]^2-g(x) = (4x^2-8x+4)-(-x^2+5x+12)\\\[f(x)]^2-g(x) = 4x^2-8x+4+x^2-5x-12](https://tex.z-dn.net/?f=%5Bf%28x%29%5D%5E2-g%28x%29%20%3D%20%284x%5E2-8x%2B4%29-%28-x%5E2%2B5x%2B12%29%5C%5C%5C%5Bf%28x%29%5D%5E2-g%28x%29%20%3D%204x%5E2-8x%2B4%2Bx%5E2-5x-12)
Combining alike terms
![[f(x)]^2-g(x) = 4x^2+x^2-5x-8x+4-12\\\[f(x)]^2-g(x) = 5x^2-13x-8](https://tex.z-dn.net/?f=%5Bf%28x%29%5D%5E2-g%28x%29%20%3D%204x%5E2%2Bx%5E2-5x-8x%2B4-12%5C%5C%5C%5Bf%28x%29%5D%5E2-g%28x%29%20%3D%205x%5E2-13x-8)
Hence,
Subtracting g(x) from the square of f(x) gives us:
The first thing we will do for this case is define variables.
We have then:
x = amount of water to evaporate.
90-x = amount of water after being evaporated.
The amount of salt is:
S = 90 * 0.15 = 13.5
The percentage of salt will be:
% S = 13.5 / (90 - x) = 25/100
Answer:
An equation can be used to find x, the number of gallons that should be evaporated is:
13.5 / (90 - x) = 25/100
Mhm thats most definitely a trick question .
Answerevulate (w,8 6)
Step-by-step explanation:
