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3 years ago

Someone help plz I need some help good at finding slope people? Anyone

Mathematics

2 answers:

fenix001 [56]3 years ago

4 0

The slope is -5/2.

since the slope is decreasing, it is negative.

mihalych1998 [28]3 years ago

3 0

Answer:

So the slope is -5/2.

Step-by-step explanation:

You want to look at the line to find the slope of it.
For slope you want to find rise/run. This is the same as: change in y/change in x. awe have 2 points (the blue dots) to find slope.
With this, let's find the change in y and the change in x.

For those 2 dots, the change in y is down 5, which means -5 (if it was up 5 it would be 5)
For change in x, it is to the right 2, which means 2 (if it was 2 to the left then it would be -2).
Therefore, the slope would be change in y/change in x which is -5/2 (the 3rd option)

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$\bf \cfrac{1+cot^2(\theta )}{1+csc(\theta )}=\cfrac{1}{sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\implies \cfrac{1+\frac{cos^2(\theta )}{sin^2(\theta )}}{1+\frac{1}{sin(\theta )}}\implies \cfrac{~~\frac{sin^2(\theta )+cos^2(\theta )}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}\implies \cfrac{~~\frac{1}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}$

$\bf \cfrac{1}{\underset{sin(\theta )}{~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}\cdot \cfrac{~~\begin{matrix} sin(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{sin(\theta )+1}\implies \cfrac{1}{sin^2(\theta )+sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\ne \cfrac{1}{sin(\theta )}~\hfill$

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