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bija089 [108]
4 years ago
8

The asymptote of the function f(x) = 3x + 1 – 2 is_________ . Its y-intercept is_____ .

Mathematics
2 answers:
mixas84 [53]4 years ago
8 0
Asymptote is y = -1

y-intercept is (0, -1)
77julia77 [94]4 years ago
6 0

Answer:

In first blank : y = - 2,

In second blank : ( 0, 1 )

Step-by-step explanation:

Given function is,

f(x)=3^{x+1}-2

The horizontal asymptote of the function f(x),

y=lim_{x\rightarrow \infty} f(x)

y=lim_{x\rightarrow \infty} 3^{x+1}-2

y=3^{\infty+1}-2

y=3^\infty - 2

y=0-2

⇒ y = -2

First option is correct.

Also, the function has no vertical asymptote,

2. For finding the y-intercept, x = 0,

f(0)=3^{0+1}-2=3-2=1

Hence, the y-intercept = (0,1)

Third option is correct.

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I think the answer is c
6 0
3 years ago
Read 2 more answers
What is the answer to 8+(-2)•9?
igomit [66]

Answer:

-10

Step-by-step explanation:

Use PEMDAS (Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction)

8 + (-2) · 9

8 - 18

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7 0
4 years ago
The health of the bear population in a park is monitored by periodic measurements taken from anesthetized bears. A sample of the
Vikki [24]

Answer:

182.167-2.03\frac{114.05}{\sqrt{36}}=143.580  

182.167+2.03\frac{114.05}{\sqrt{36}}=220.754  

So on this case the 95% confidence interval would be given by (143.580;220.754)  

Step-by-step explanation:

Assuming the following dataset:

77, 349,417,349, 167 , 225, 265, 360,205

145,335,40,139, 177,108, 163, 202, 22

123,439, 125,135, 86,43, 217,49, 156

119,178, 151, 61, 350, 312, 91, 89,89

We can calculate the sample mean with the followinf formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}= 182.167

And the sample deviation with:

s = \sqrt{\frac{\sum_{i=1}^n (X_i-\bar X)^2}{n-1}}=114.05

The sample size on this case is n =36.

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=182.167 represent the sample mean  

\mu population mean (variable of interest)  

s=114.05 represent the sample standard deviation  

n=36 represent the sample size    

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

The point estimate of the population mean is \hat \mu = \bar X =182.167

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=36-1=35  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,35)".And we see that t_{\alpha/2}=2.03  

Now we have everything in order to replace into formula (1):  

182.167-2.03\frac{114.05}{\sqrt{36}}=143.580  

182.167+2.03\frac{114.05}{\sqrt{36}}=220.754  

So on this case the 95% confidence interval would be given by (143.580;220.754)  

5 0
3 years ago
PLEASE HELP I WILL GIVE U BRAINZ DAS WEIRD DAT MEAN U A ZOMBIE pic below
fenix001 [56]

Answer:

your answer would be B :)

Step-by-step explanation:

6 0
3 years ago
Under the translation t(-7,3) the point (1,6) will become (-6,-3) true or false?
Alekssandra [29.7K]

false

under the given translation

the point (1, 6 ) → (1 - 7, 6 + 3 ) → (- 6, 9 )


3 0
4 years ago
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